Question

Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by

Answer 1

Answer:

B. $\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

$W = \frac{3}{25}$

$X = \frac{\sqrt{3}}{11}$

$Y = \frac{9}{100}$

$Z = \frac{\pi}{24}$

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

$W = \frac{3}{25}$

$W = 0.12$

$X = \frac{\sqrt{3}}{11}$

Take square root of 3

$X = \frac{1.73205080757}{11}$

$X = 0.15745916432$

$X = 0.16$ --- approximated

$Y = \frac{9}{100}$

$Y = 0.09$

$Z = \frac{\pi}{24}$

Take π as 3.14

$Z = \frac{3.14}{24}$

$Z = 0.13083333333$

$Z = 0.13$  --- approximated

List out the results, we have:

$W = 0.12$    $X = 0.16$    $Y = 0.09$    $Z = 0.13$

Order from greatest to least, we have:

$X = 0.16$     $Z = 0.13$      $W = 0.12$       $Y = 0.09$

Hence, the order of arrangement is:

$X = \frac{\sqrt{3}}{11}$     $Z = \frac{\pi}{24}$      $W = \frac{3}{25}$      $Y = \frac{9}{100}$

i.e.

$\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$