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Gnesinka [82]
3 years ago
14

The product of 3 and 12 what is the expression?

Mathematics
2 answers:
Serggg [28]3 years ago
4 0

Answer:

3×12

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

MArishka [77]3 years ago
3 0

Answer:

36

Step-by-step explanation:

The product is the two numbers multiplied together so the answer is 3*12=36

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A sprinter ran 100 meter dash in 10.92 seconds. What was the sprinters speed in miles per hour
tresset_1 [31]
The formula for working out speed :

speed = distance ÷ time.

substitute the numbers : 100m ÷ 10.92s.

give your answer in meters per second ( m/s )

the answer I got while working this out was:
9.2 m/s.
8 0
3 years ago
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(PLEASE!!!!) The congruency of MNO and XYZ can be proven using a reflection across the line bisecting OZ. However, this congruen
finlep [7]

Explanation:

Only the reasons need be given here, as the statements are already given in your figure.

  1. Given
  2. Given
  3. Given
  4. Definition of congruent line segments
  5. Symmetric property of congruence
  6. Addition and substitution properties of equality*
  7. Segment addition theorem
  8. Definition of congruent line segments
  9. AAS congruence postulate

_____

* The addition property says if A=B, then A+C=B+C. The substitution property further says if C=D, then A+C=B+D (D can be substituted for C). IMO, both properties are needed together to get from A=B and C=D to A+B=C+D.

6 0
3 years ago
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Which of the following pairs of numbers contain like fractions?
saveliy_v [14]
Like fractions are fractions that have the same denominator. In option D, both denominators are 7. Therefore, they are like fractions.
7 0
3 years ago
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A.The observation deck of tall skyscraper 370 m above the street. Determine the time required for a penny to free fall from the
Ainat [17]

Answer:

8.68 seconds

Step-by-step explanation:

Given:

Height of the deck above the street, s = 370 m

Since the condition is of free falling

thus,

initial speed, u = 0

Acceleration of the penny = acceleration due to gravity, g = 9.81 m/s²

Now,

from Newton's equation of motion, we have

s=ut+\frac{1}{2}at^2

here,

s is the distance

a is the acceleration

t is the time

on substituting the values, we get

370=0\times t+\frac{1}{2}\times9.81\times t^2

or

t² = 75.433

or

t = 8.68 seconds

8 0
4 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
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