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3 years ago

Consider the figure below. I need need help with what’s the slope of TR is:

Mathematics

1 answer:

Keith_Richards [23]3 years ago

5 0

Answer:

The slope of RT is: m = 1

Step-by-step explanation:

Given

R(-3, 1)

T(2, 6)

Determining the slope between (-3, 1) and (2, 6)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-3,\:1\right),\:\left(x_2,\:y_2\right)=\left(2,\:6\right)$

$m=\frac{6-1}{2-\left(-3\right)}$

Refine

$m=1$

Therefore, the slope of RT is: m = 1

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The amount of interest accrued on a $7,000 loan with 6% interest after t years.

Misha Larkins [42]

Answer:

$420t

Step-by-step explanation:

Given data

Principal= $7000

Rate= 6%

Time= t years

The expression for the amount is

Simple interest= PRT/100

Sustitute

Simple interest= 7000*6*t/100

Simple interest= 42000t/100

Simple interest= 420t

Hence the amount after t years is $420t

6 0

3 years ago

Joe went shopping for a guitar in Fairfax. He purchased one originally priced at $240 but discounted 80%. If sales tax in Fairfa

puteri [66]

Answer:

$52.44

Step-by-step explanation:

So here is the explanation. $240•.80= 192 (80% as a decimal is .80) 240-192=48. 48•.0925=4.44 which you add 48, and get a sum of $52.44

Hope this helps :)

4 0

3 years ago

Read 2 more answers

The lengths of the sides of a square are represented by the expression 3x + 1 cm. The perimeter of the square is 28 cm. What is

pshichka [43]

Answer:

x=2

Step-by-step explanation:

Perimeter of a square = 4*(side of the square)

28 = 4*(3x+1)

28 = 12x + 4

28- 4 = 12x

24 = 12x

x =2

7 0

3 years ago

A reflection changes the shape of a figure. True False

Sveta_85 [38]

Answer:

False

Step-by-step explanation:

A reflection does not change the shape of a figure.

For example, If you look into a mirror, you are looking at a reflection of yourself, but your face doesn't change into something else...! :)

8 0

3 years ago

Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

3 years ago