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asambeis [7]
2 years ago
14

A movie theater seating is arranged with 15 seats in the front row, 14 seats in the middle row, and 26 seats in the back row. Th

e ticket-taker randomly assigns seats to people as they enter the theater. What is the probability that the first person who enters the theater will be assigned a seat in the front row? Ratio Answer in simplest form.
Mathematics
1 answer:
Kryger [21]2 years ago
6 0

Answer:

3/11

Step-by-step explanation:

i did this question it 3/11

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****BRAINLIEST GOES TO THE FIRST CORRECT ANSWER****
erik [133]
Given
Segment Addition Postulate
Transitive Property of Equality
4 0
3 years ago
I don't know how to do this. I forget plz help
Leno4ka [110]
Ok so 
0.5%=0.005
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Hope this helps
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If you continue with the same formula with a different problem then you will get it correct 
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3 years ago
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Andre is setting up rectangle tables for a party. He can fit 6 chairs around a single table. Andre lined up 10 tables end to end
IRINA_888 [86]
If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
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5 0
3 years ago
F=-GMn/D^2 solve for M
notka56 [123]
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5 0
3 years ago
6) A standard deck has 52 cards, and contains 13 cards of each of the four suits: diamonds, spades, hearts, and clubs. What is t
Crazy boy [7]

Answer:

\dfrac{12}{51}\cong\dfrac{4}{17}

Step-by-step explanation:

You have 52 cards in a deck and 13 cards of each suit.

The probability of picking a diamond in a complete deck of cards is:

\dfrac {13}{52}

Or the probability is 13 put of 52.

Since you took out 1 diamond card already there would be only 51 cards left and 12 diamond cards left. So you would have a probability of:

\dfrac{12}{51}

If we simplify it you will have a probability of:

\dfrac{4}{17}

6 0
2 years ago
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