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asambeis [7]
2 years ago
14

A movie theater seating is arranged with 15 seats in the front row, 14 seats in the middle row, and 26 seats in the back row. Th

e ticket-taker randomly assigns seats to people as they enter the theater. What is the probability that the first person who enters the theater will be assigned a seat in the front row? Ratio Answer in simplest form.
Mathematics
1 answer:
Kryger [21]2 years ago
6 0

Answer:

3/11

Step-by-step explanation:

i did this question it 3/11

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Charra [1.4K]

Answer:  -418, 728, 446, -429, 1159, -696

Step-by-step explanation:

1. n = -199 - 219 = \boxed{-418}.

2. m = 438 - (-290) = 438 + 290 = \boxed{728}.

3. 128 - (-318) = 128 + 318 = \boxed{446}.

4. The sum of 429 and 429 is 429+429 = 858. We need to subtract this from 429, so 429 - 858 = \boxed{-429}.

5. The sum of 510 and 319 is 510+319 = 829. Subtracting -330, we get 829 - (-330) = 829 + 330 = \boxed{1159}.

6. Call the unknown number "\star". Then \star + 298 = -398, so \star = -398 - 298 = \boxed{-696}. (Think about it.)

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3 years ago
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Just pick any point on the blue triangle and count how many you move to get to that same point on the red triangle.
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(4x2) + (3x1)=11
I think that's right, can you have a plus sign
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