Given
Segment Addition Postulate
Transitive Property of Equality
Ok so
0.5%=0.005
0.005x=8
x=8/0.005
x=1600
8 is 0.5% of 1600
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If you continue with the same formula with a different problem then you will get it correct
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If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
M=FD^2/(-Gn)
here is the solution
Answer:

Step-by-step explanation:
You have 52 cards in a deck and 13 cards of each suit.
The probability of picking a diamond in a complete deck of cards is:

Or the probability is 13 put of 52.
Since you took out 1 diamond card already there would be only 51 cards left and 12 diamond cards left. So you would have a probability of:

If we simplify it you will have a probability of:
