Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
Answer:
=
1
2
x2+
20
3
x−3
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
Given the points J (1,-10) and K (7, 2)
From the section formula

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is obtained using the formula:

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is 0.
Answer:
C
Step-by-step explanation:
A constant correlation is essentially when the points on a scatter plot do not show any type of pattern or correlation; the points are literally scattered rather randomly, which would cause the graph to neither increase nor decrease.
Meanwhile, a positive correlation means that the points on the plot follow a line with a positive slope. In other words, it increases to the right.
Thus, the answer is C.
Hope this helps!
It’s 1
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