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Evgen [1.6K]
3 years ago
11

What is the exact value of sin^-1 (0) and how do you get that?

Mathematics
2 answers:
kvv77 [185]3 years ago
6 0

Answer:

See Explanation

Step-by-step explanation:

let \: y =  { \sin}^{ - 1} (0) \\  \\  \therefore \:  \sin \: y = 0 \\  \\ \therefore \:  \sin \: y =  \sin \: 0  \degree\\( \because \: \sin \: 0  \degree= 0)  \\  \\  \therefore \: y \:  = 0 \degree \\  \implies \: { \sin}^{ - 1} (0) = 0 \degree  \\  \\ in \: the \: same \: way \\  \\ { \sin}^{ - 1} (0) = 180 \degree  \\  \\{ \sin}^{ - 1} (0) = 360 \degree  \\  \\

AveGali [126]3 years ago
4 0

Answer:

B.) 0

Step-by-step explanation:

just took the test on edg and got 100%

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