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BabaBlast [244]
3 years ago
13

A cohort study was conducted to study the association of coffee drinking and anxiety in a population-based sample of adults. Amo

ng 10,000 coffee drinkers, 500 developed anxiety. Among the 20,000 non-coffee drinkers, 200 cases of anxiety were observed. What is the relative risk of anxiety associated with coffee use?
Mathematics
1 answer:
azamat3 years ago
6 0

Answer: Relative risk of anxiety associated with coffee use is 5 times the anxiety associated with non coffee use.

Step-by-step explanation:

Since we have given that

Number of coffee drinkers = 10000

Number of whom developed anxiety = 500

Number of non coffee drinkers = 20000

Number of whom developed anxiety = 200

So, probability of getting anxiety from coffee drinkers = \dfrac{500}{10000}=0.05

Probability of getting anxiety from non coffee drinkers = \dfrac{200}{20000}=0.01

so, Relative risk of anxiety associated with coffee use is given by

\dfrac{0.05}{0.01}=5

Hence, Relative risk of anxiety associated with coffee use is 5 times the anxiety associated with non coffee use.

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belka [17]

A) Variance = 10.24

B) Standard Deviation = 3.2

One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.

TIME         FREQUENCY(f)  MIDPOINT(x)    d    d²     fd              fd²

0 - 0.9         43                          0.45             -3     9     -129            387

1.0 - 1.9         17                           1.45              -2    4     -34                68

2.0 - 2.9       19                            2.45             -1     1       -19               19

3.0 - 3.9        18                            3.45             0     0       0                  0

4.0 - 4.9        14                            4.45              1      1        14               14

5.0 -5.9         16                            5.45              2     4        32             64                            

∑f = 127                                                              

∑fd = -136  

∑fd² = 552

d = \frac{x - 3.45}{1}

Standard Deviation = \sqrt \frac{fd^{2} }{N} - \sqrt \frac{(fd)^{2} }{N} * i

\sqrt \frac{552}{127} -\sqrt (\frac{-136}{127})^{2}   * 1

√4.35 - √1.15

Standard Deviation = 3.2

(SD)² = (3.2)² = 10.24

Variance = 10.24

To know more about standard deviation, refer to this link :

brainly.com/question/12402189

#SPJ1

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1 year ago
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What are interest rates? Please explain.
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