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sleet_krkn [62]
3 years ago
6

Y

Mathematics
1 answer:
irakobra [83]3 years ago
7 0
What is the question??
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P: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q?
Lesechka [4]
The inverse is b.  If 4x+1 .NE. 61, then x-5 .NE.10
3 0
3 years ago
Read 2 more answers
It’s confusing, would the answer be square root 7 over 4?
Colt1911 [192]

Answer:

\tan U = 1

Step-by-step explanation:

\text{Apply Pythagorean theorem,}\\\\~~~~~~\text{Hypotenuse}^2 = \text{Base}^2 + \text{Perpendicular}^2\\\\\implies UT^2 = UV^2 +VT^2\\\\\implies UV^2 = UT^2 -VT^2\\\\\implies UV^2 = \left(7\sqrt 2 \right)^2 - 7^2\\\\\implies UV^2 = 49(2)-49\\\\\implies UV^2 = 49\\\\\implies UV = \sqrt{49} \\\\ \implies UV = 7

\text{Now,}\\\\~~~~~~~~\tan \theta = \dfrac{\text{Perpendicular}}{\text{Base}}\\\\\\\implies \tan U = \dfrac{7}{7}\\\\\\\implies \tan U = 1

4 0
2 years ago
a bag contains 15 dark chocolates, 16 caramel chocolates, and 19 milk chocolates. the probability that amber’s teacher distribut
Yuri [45]
The total number of chocolates is 15 + 16 + 19 = 50

There are 15 + 16 = 31 [dark chocolates + caramel chocolates]

The probability of picking one of them is 31 / 50.


8 0
3 years ago
Read 2 more answers
15a^2 + 14a -8 use A.C method
bekas [8.4K]
Hello there!

A C method : you multiply the A and C -> find the factors of AC that can add                          up to B. (a² + bx + c)

15a² + 14a - 8

you multiply 15 and -8 = -120
Find the two factors of -120 that adds up to 14.
We could used 20 and -6.
So we can split the original equation to this:

15a² + 20a - 6a - 8
Now, we use grouping method.
Let's group 15a² + 20a  and -6a - 8.

15a² + 20a can be factored like this :
5a(3a + 4)

-6a - 8 can be factored like this :
-2(3a + 4)

So it is 5a(3a + 4) × -2(3a + 4)
We can simplify this into this :
(5a - 2)(3a + 4)


So your final answer is (5a - 2)(3a + 4).
Hope this helped! :)
8 0
3 years ago
What will you use if you are looking for the space bounded by a rectangle A. 2(I + w) B. S² C. B × h ________ 2 D. I × w
Rus_ich [418]

Answer:

A. 2(I + w)

Step-by-step explanation:

The space bounded by a rectangle is its perimeter. So, I would use 2(l + w) where l = length of rectangle and w = width of rectangle.

As an example, suppose we have a rectangle of length, l = 40 meters and width, w = 20 meters and seek to find its perimeter that is, the space bounded by the rectangle, we substitute the values of l and w into the equation for the perimeter.

So, P = 2(l + w)

substituting the values of l and w into the equation, we have

P = 2(l + w)

P = 2(40 m + 20 m)

P = 2(60 m)

P = 120 m

So the space bounded by the rectangle is 120 m.

So, to find the space bounded by a rectangle, we use 2(l + w).

So, the answer is A.

5 0
3 years ago
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