Answer:
1. Artwork of the child participants can be displayed as Picture.
Explanation:
The Art work is painting and filling different colors in different images and objects. Child make different pictures of homes, objects, fruits and vegetables and then colored them accordingly. This type of art work is displayed as picture. This work could not be displayed in the form of tables and lists and also could not shown as graphics.
Answer:
2. The changing image of public transportation is displayed as Graphics.
Explanation:
In Graphics, different images has been designed on different tools by graphic designers to display some problem and its solution in visuals. Different tools are there to make visuals. Changing image of bus transportation is also a transition from old transport system to new transportation system. So, it should displayed in the form of graphics.
Answer:
Illustrative comparison of data from the year 2010-2013 can be displayed in the form of word tables and lists.
Explanation:
In tables and list different data has been placed in specific order for the purpose of analysis of data. These tables are also designed to compare different values and things. So, the data from the year 2010-2013 can be displayed in the form of tables and list so that it can be compared and analyze from different aspects.
Answer:
1. Java is Simple · 2. Java is an Object-Oriented Programming language · 3. Java is a secure language · 4. Java is cheap and
Explanation:
Answer:
I was actually just looking to help with someone's schoolwork. . .
Explanation:
Answer:
Check the explanation
Explanation:
CPI means Clock cycle per Instruction
given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M
Execution time is given by following Formula.
Execution Time(CPU time) = CPI*Instruction Count * clock time = 
a)
for system A CPU time is 1.3 * 100, 000 600 106
= 216.67 micro sec.
b)
for system B CPU time is 
= 333.33 micro sec
c) Since the system B is slower than system A, So the system A executes the given program in less time
Hence take CPU execution time of system B as CPU time of System A.
therefore
216.67 micro = =
Instructions = 216.67*750/2.5
= 65001
hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A
