Answer:
The function is as follows:
void readAndConvert(){
int n; string symbol,name;
cin>>n;
cin>>symbol;
cin.ignore();
getline (cin,name);
vector<string> trades;
string trade;
for (int inps = 0; inps < n; inps++){
getline (cin,trade);
trades.push_back(trade);}
cout<<name<<" ("<<symbol<<")"<<endl;
for (int itr = 0; itr < n; itr++){
string splittrade[3]; int k = 0;
for(int j=0;j<trades.at(itr).length();j++){
splittrade[k] += trades.at(itr)[j];
if(trades.at(itr)[j] == ' '){
k++; }}
cout<<splittrade[2]<<": "<<floor(stod(splittrade[1]) * stod(splittrade[0]))<<endl; }
}
Explanation:
See attachment for complete program where comments are used to explain each line
Answer:
account recovery
Explanation:
account recovery, provides options for getting access to your old password or resetting the account to a temporary password; users will change to a permanent password upon first login.
Answer:
Technology > Network report. All traffic > Source/Medium report.
Explanation:
hope this helps
Answer:
miles_gallon = float(input("Enter car's miles/gallon: "))
dollars_gallon = float(input("Enter gas dollars/gallon: "))
print("Gas cost for 20 miles is $", (20 / miles_gallon) * dollars_gallon)
print("Gas cost for 75 miles is $", (75 / miles_gallon) * dollars_gallon)
print("Gas cost for 500 miles is $", (500 / miles_gallon) * dollars_gallon)
Explanation:
*The code is in Python.
Ask the user to enter the car's miles/gallon and gas dollars/gallon
Calculate the gas cost for 20 miles, divide 20 by miles_gallon and multiply the result by dollars_gallon, then print it
Calculate the gas cost for 75 miles, divide 75 by miles_gallon and multiply the result by dollars_gallon, then print it
Calculate the gas cost for 500 miles, divide 500 by miles_gallon and multiply the result by dollars_gallon, then print it
Answer: The difference between these two types of abaci are the number the beads.
Explanation:
have a great day or night
