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Nadusha1986 [10]
3 years ago
7

WHATS #1 i need it soon:((

Chemistry
1 answer:
pentagon [3]3 years ago
5 0
However, antibiotics can also have harmful side effects, increase bacterial resistance, and sometimes even work against your immune system. Antibiotics are not effective against viruses,

Hence the answer is C
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Question 116 g of sunflower oil is
Luba_88 [7]
<h2>Answer:  125.41 mL</h2>

Explanation:

Volume = mass ÷ density

             =  116 g  ÷  0.925 g/mL

             =  125.41 mL

<h3>A 116 g of sunflower oil of 0.925 g/mL has a volume of 125.41 mL.</h3>
7 0
3 years ago
Pllllllsssssssssss helpppp Determine the Mass Number of the Following Elements:
aleksklad [387]
Al- 28
B- 11
C- 14
Sc- 46
Na- 24
Mass number= proton+neutrons
5 0
3 years ago
The value of A for an atom containing 12 protons, 12 electrons and 16 neutrons is
Zepler [3.9K]

Answer: A = atomic number = 12

Explanation: A (atomic number) defines the chemical element. It is the numbervof protons or electrons. Neutron numbers may vary, produving isotopes of differing atomic mass. This isotope has atomic mass 28. The atomic number 12 = carbon. C28 does not really exist. If it could be produced it would be radioactive with an almost zero halflife.

3 0
3 years ago
The most characteristic property of the noble gases is that they
Brut [27]

Answer:

odorless and colorless

Explanation:

its their properties

7 0
3 years ago
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring
iren2701 [21]

Answer:

1.20 V

Explanation:

The standard cell potential is calculated from the expression

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction

The species that will be reduced is the one with the higher standard reduction potential and the species that will be oxidized will be the one with the more negative reduction potential.

Thus for our question we will have

oxidation:

Pb(s)  →   Pb2+(aq) + 2 e-       ε⁰ oxidation       =  -   ε⁰  reduction

                                                                          =   - ( - 0.13 V ) = + 0.13 V

reduction    

Br2(l) + 2 e- → 2 Br-(aq)           ε⁰  reduction     = +1.07 V

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction = + 0.13 V + 1.07 V  = 1.20 V

4 0
3 years ago
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