your alien friend from planet xenon is visiting and wants to learn how to breed pea plants you show your friend a recent batch o
1 answer:
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<u>Answer:</u>
2.07 grams
<u>Explanation:</u>
We know that the molecular mass of is 138.205 grams.
In order to find out how many grams we need to make 200 mL having a potassium ion concentration of 0.150, we need to find the number of moles first.
M = moles / liters
0.150 = x / 0.200
x = 0.03 moles
Since there are 2 potassium atoms in each molecule of so we will divide this number by half and multiply it by the molecular mass.
0.03/2 = 0.015 moles
Mass of needed = 0.015 × 138.205 = 2.07 grams
Question is incomplete, complete question is;
A 34.8 mL solution of (aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of ? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.
Answer:
0.044 M is the molarity of (aq).
Explanation:
The reaction taking place here is in between acid and base which means that it is a neutralization reaction .
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
0.044 M is the molarity of (aq).