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Ulleksa [173]
3 years ago
6

Unit rate of 12 in 4

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0

Answer: 3

Step-by-step explanation:

i think   im not 100% sure

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Plz help I need with question I give thanks
Alenkasestr [34]

Answer:

I believe X = 8

Step-by-step explanation:

you would use the equation D + C = B or

48 + 5x + 11 = 11x + 11

then subtract 11 from each side leaving

48 + 5x = 11x

then you would subtract 5x from each side, leading to

48 = 6x

48 ÷ 6 = <u>8</u>

8 0
3 years ago
The vertices of figure BCDE have coordinates B(4, 4) , C(−4, 4), D(−4, −4) , and E(4, −4) . The vertices of figure B'C'D'E' have
Fiesta28 [93]
The transformation used was a translation because the numbers changed. Since the x is becoming a smaller number the figure is moving to the left and since the y is getting larger the figure is also moving up. So the answer is: translation, 2 units to the left and 2 units up
4 0
3 years ago
Probability and statistics
Hatshy [7]

Answer:

First: 4/10 aka 2/5

Second: 3/9 aka 1/3

3 0
2 years ago
Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.
maksim [4K]

Answer:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is ar^{n-1}

Therefore the sum of the first n terms is:

\Sigma_{k=1}^{n}(ar^{k-1})

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

5 0
3 years ago
Which statement is true about point Y?
Viefleur [7K]

Answer:C

Step-by-step explanation:

3 0
3 years ago
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