Answer:
0.0329g of quinine
Explanation:
If 25.0ppm of quinine solution had a fluorescence of 193, the solution that had a fluorescence of 127 has as concentration:
127 × (25.0ppm / 193) = <em>16.45ppm</em>
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As the solution was diluted from 50.0mL to 200.0mL, the sample tonic of water contains:
16.45ppm × (200.0mL / 50.0mL) = 65.8 ppm
As the original solution contains 500.0mL, mass of quinine is:
0.5000L × (65.8mg / L) = 32.9mg ≡<em> 0.0329g of quinine</em>
Accepting that you're utilizing NaOH answer for its essential properties in corrosive/base science, I can expect that pH is of significance. When you have an institutionalized arrangement of say 1M (molar) focus NaOH arrangement and you put it into a dry burette to do a titration or something, you are expecting that the arrangement has a 1 mol of NaOH for each one liter of arrangement (molarity = mols/liters).