I'm going to separate this into sections so it makes more sense for you to read. For the problems with π where you have to round, ask your teacher where to round, unless your textbook specifies it:
A – 100 cm^2
To calculate area of squares, you multiply l • w. It's a square, so all sides are equal, and since we know that one side = 10 cm, the area is 10 • 10 = 100
B – πr^2 (not sure if the r shows up very well, so I'm retyping it in words - pi • radius squared)
C – 25π cm^2 or an approximate round like 78.54 cm^2 (ask your teacher about this – it could be to the nearest tenth, hundredth, etc.)
To find the area of a circle, you must follow the formula πr^2. In this case, the diameter is 10. The radius is half the diameter, so to substitute the values you must find 10 ÷ 2 = 5. So the radius is 5 cm. From there you can substitute r for 5, ending up with π • 5^2. 5^2 = 25, so the area is 25π, or about 78.54, depending on where the question wants you to round.
D – An approximate round (to the nearest hundredth it is 21.46 cm^2)
To find the area of the shaded region, just subtract the circle's area from the square's area, or 100 – 25π ≈ 21.46. Again, though, ask your teacher about where to round, unless your textbook specifies it.
E – dπ (diameter • pi)
F – 10π cm^2 or an approximate round like 31.42 cm^2
The diameter is 10. 10π ≈ 31.42
Hope this helps!
Answer: 54 square feet
Step-by-step explanation:
To find perimeter of a rectangle we must use the formula l+l+w+w=p where l and w represent width and length
Since we know length and width is x=12 just substitute so
15+15+12+12=54 so 54 is the perimeter
Answer: for every 1 cups of oats there are 25 grams of almonds
Step-by-step explanation:
u would divide 50 by 2 and divide 2 by 2
Answer:

Step-by-step explanation:
Please see the picture below.
1. Given the function f(x) = |x|, applying a vertical stretch with scale factor
, we have the transformed function:

2. Applying a translation of 3 units to the right, we have:

3. Finally applying a translation down of 1 unit, we have:
