Presumably our goal is to show PRQ=SRQ, PQR=SQR and QR=QR for ASA.
A. QR=QR is the reflexive property; things are congruent to themselves, TRUE
B. We need to prove that, but it doesn't have anything to do with the symmetric property.
C. PQ=SQ isn't something we'd need to show for our ASA proof
D. Again, not the symmetric property.
Answer: A
Answer:
w ≥ 6
l ≥ 11
Step-by-step explanation:
The perimeter of a rectangle is equal to P = 2l+2w where l=length and w=width. Here the length is 5 feet longer than the width or 5+w. This means the width is w. Substitute P = 34, l=5+w and w into the perimeter equation. Then solve for w.
34 ≤ 2*(5+w) + 2w
34 ≤ 10+2w+2w
34 ≤ 10+4w
24 ≤ 4w
6 ≤ w
This means the width must be at least 6 so the solution is w ≥ 6.
To find the length substitute 6 into l ≤ 5+w.
l ≤ 5 + 6
l ≤ 11
The length is l ≥ 11.
Answer:
Bbbbbbbbbbbb
Step-by-step explanation:
Answer:
20 - 0.9u = 4.7
-0.9u = 4.7 - 20
-0.9u = -15.3
Divide both sides by - 0.9
u = 17
Hope this helps.
