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SIZIF [17.4K]
3 years ago
13

The spinner shown is ​

Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

where is the spinner

Step-by-step explanation:

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Given that v= 5,-4,4) and w = 10,-27), evaluate you
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The answer for your question is D
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(4 x 10) + (2 x 104)<br> Give your answer in standard form
Goshia [24]

Answer: =248x

Step-by-step explanation: Hope this help :D

Let's simplify step-by-step.

4x(10)+2x(104)

=40x+208x

Combine Like Terms:

=40x+208x

=(40x+208x)

=248x

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How do I find the product when multiplying with decimals<br><img src="https://tex.z-dn.net/?f=0.36%20%5Ctimes%202.4" id="TexForm
stellarik [79]

Step 1:

first let us convert the two decimals into fractions.

0.36=36/100 (since there are two digits after decimal point we divide by 100)

2.4=24/10 (since there are one digit after decimal point we divide by 10)

now we can multiply the fractions

\frac{36}{100}×\frac{24}{10}

multiplying numerator with numerator and denominator with denominator:

\frac{36*24}{100*10}

=\frac{864}{1000}

Now we can convert this back to decimal

864/1000=0.864, moving decimal three digits to the left since we have three zeros in the denominator that is 1000.

Answer=0.864

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3 years ago
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4 0
3 years ago
What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"
salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is 27 + 64x^{3}

Now, the equation is 27 + 64x^{3} = 0

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be - \frac{3}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  

Again, we have to solve the difference of two cubes which is 64m^{3} - 1

Now, the equation is 64m^{3} - 1 = 0

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be \frac{1}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  (Answer)

8 0
3 years ago
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