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Luba_88 [7]
2 years ago
10

What is this answer + solving step

Mathematics
2 answers:
Ksivusya [100]2 years ago
6 0
Um i think 20 but if it’s wrong then sorry
Lena [83]2 years ago
4 0
I believe it is 20 as well
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Find the value of x in terms of a
Tatiana [17]

Answers:

a= 5x±\sqrt{25x^{2} +24u^{2} \\

 ------------------------------

                6  

u=± \sqrt{2a(3z-5x}

  -------------------------

                2

<h2>Brainliest please!!!! It took me a while to figure this out!</h2>
7 0
3 years ago
7. what is the volume of this object
OverLord2011 [107]

Answer:

Dont knowwwww

Step-by-step explanation:

5 0
3 years ago
What is the domain and range of each function graohed below?
andriy [413]
Domain is the x values you can use
range is the y values



a.
the domain
hmm, seems to be all real numbers except for at x=0, it gets really close tho
so D=(-∞,0)U(0,∞)

range is all real numbers except for y=0, it gets really close tho
R=(-∞,0)U(0,∞)



b.
domain
that empty circle means something like < or >
goes from 5 to 6, not including 5
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range is from -4 to 2, not including -4
range is R=(-4,2]
5 0
3 years ago
Read 2 more answers
One factor of the polynomial 2x^3 - 3x^2 - 3x + 2 is ( x - 2 ). Which expression represents the other factor, or factors, of the
Georgia [21]

Answer:

Option (D)

Step-by-step explanation:

Given polynomial is,

2x³ - 3x² - 3x + 2

If (x - 2) is the factor of the given polynomial,

By synthetic division we can get the other factor.

2 |  2     -3       -3       2    

 

    <u>         4         2      -2          </u>

     2      1         -1        0

Therefore, other factor of the given polynomial is (2x² + x - 1)

Now (2x² + x - 1) = 2x² + 2x - x - 1

                           = 2x(x + 1) -1(x + 1)

                           = (2x - 1)(x + 1)

Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)

Option (D) will be the answer.

4 0
3 years ago
Please help me , please
Tatiana [17]

Answer:

c is correct

Step-by-step explanation:

5 0
3 years ago
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