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Studentka2010 [4]
4 years ago
15

How do you create a truth table to prove that for any statement, p,~(~p) equals p?

Mathematics
1 answer:
Fynjy0 [20]4 years ago
3 0
If p is true, then \sim p is false, which in turn means \sim(\sim p) is true.

If p is false, then \sim p is true, and so \sim(\sim p) is false.

So, because p\equiv\sim(\sim p) in both cases, the statement is a tautology (always true).

If you were to put this in a table, you would have one column each for p,\sim p,\sim(\sim p). In the first column (p) you can think of p as an independent variable that can only take two values, true and false. In the next column (\sim p), you would negate the value in the previous column. And so on.

It should roughly look like this:

p ... ~p ... ~(~p)
T ...  F  ...    T
F ...  T  ...    F
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Hello can someone please help me
QveST [7]
5/6(3)-1/6 = 5/2-1/6=15/6-1/6=14/6=7/3
5 0
3 years ago
Which is the right answer?????
Inga [223]

Answer: A

Step-by-step explanation: put it into point slope-form

y-ysub1=m(x-xsub1)

m=slope=(-2-3)/(2-(-1))=-5/3

ysub1 is 3 and xsub1 is -1

so substitute: y-3=-5/3(x-(-1))

y-3=-5/2(x+1)

6 0
3 years ago
6.3.12
Semenov [28]

Answer:

S = (4,-9)

Step-by-step explanation:

Given

T = (0,5)

Midpoint = (2,-2)

Required

Find S

Midpoint is calculated as:

Midpoint = 0.5(x_1 + x_2,y_1+y_2)

So, we have:

(2,-2)= 0.5(0+ x_2,5+y_2)

<em>Where x2 and y2 are the coordinates of S</em>

Multiply through by 2

2 * (2,-2)= 2 * 0.5(0+ x_2,5+y_2)

(4,-4)= (0+ x_2,5+y_2)

(4,-4)= (x_2,5+y_2)

By comparison:

x_2 = 4

5 + y_2 = -4

y_2 = -4-5

y_2 = -9

So:

S = (4,-9)

7 0
3 years ago
Question
Yanka [14]

Answer:

b or 150

Step-by-step explanation:

3 0
4 years ago
Can anybody help me? I would really appreciate it
irina [24]
It is the last answer because both x and y are adding by 1
4 0
3 years ago
Read 2 more answers
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