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Karolina [17]
3 years ago
7

A couple just had twin boys, but they can’t decide between the names Mike, Mark, Peter, Paul, Sam, and Sonny. If the couple rand

omly chooses names for the 2 boys from the names listed, what is the probability that the first boy born will be named Sam and the second boy born will be named Mark? Assume that the boys will not have the same name.
Mathematics
1 answer:
Virty [35]3 years ago
3 0

Answer:

The probability is 1/30 or 0.0333

Step-by-step explanation:

For calculating the probability we need to make a division between the number of ways in which the first boy born is named Sam and the second boy born is named Mark and the total number of ways in which the couple can name their children.

To calculate the total number of  ways in which the couple can name their children, we can use the rule of multiplication as:

<u>          6             </u> *  <u>            5              </u>     =    30          

First boy Born       2nd Boy Born

Because we have 6 options for the name of the first boy and 5 options for the name of the second boy.

Additionally, In just one option from this 30, the first boy is named Sam and the second is named Mark.

So, the probability is calculate as the division between 1 and 30 as:

P=\frac{1}{30} = 0.0333

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During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time
Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

\frac{dP}{dt} = Pr

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

\frac{dP}{P} = r dt

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\ln{P} = rt + K

Applying the exponential to both sides:

P(t) = Ke^{rt}

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

P(t) = 300e^{rt}

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

P(t) = 300e^{rt}

1000 = 300e^{24r}

e^{24r} = \frac{1000}{300}

e^{24r} = \frac{10}{3}

\ln{e^{24r}} = \ln{\frac{10}{3}}

24r = \ln{\frac{10}{3}}

r = \frac{\ln{\frac{10}{3}}}{24}

r = 0.05

So

P(t) = 300e^{0.05t}

At what time t is the population 500?

This is t for which P(t) = 500. So

P(t) = 300e^{0.05t}

500 = 300e^{0.05t}

e^{0.05t} = \frac{500}{300}

e^{0.05t} = \frac{5}{3}

\ln{e^{0.05t}} = \ln{\frac{5}{3}}

0.05t = \ln{\frac{5}{3}}

t = \frac{\ln{\frac{5}{3}}}{0.05}

t = 10.22

The population is of 500 after 10.22 hours.

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2 years ago
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Answer:

c. 21/200

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Answer:

Step-by-step explanation:

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Whenever p < alpha we reject our null hypothesis.  Otherwise we accept our null hypothesis.

Hence p should be high to accept null hypothesis

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D False

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Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

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we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

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we have:

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lets apply square root on both sides of the equation:

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finally we have:

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