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telo118 [61]
3 years ago
8

Find the least common multiple of 4 and 20

Mathematics
2 answers:
Alexxandr [17]3 years ago
4 0

Answer:

Technically, it could be one. since one goes into everything but I'm not sure if you're teacher accepts that answer. So 2. 2 goes into 4 two times and 2 goes into 20 ten times

Step-by-step explanation:

Svetach [21]3 years ago
3 0

Answer:

Heya mate....

Step-by-step explanation:

This is ur answer.....

<h2>LCM of 4 and 20 is 20.</h2>

Hope it helps!

Brainliest pls!

Follow me :)

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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
1. Provide reasons for the proof. Given:
marysya [2.9K]
Given that <span>Line m is parallel to line n.
We  prove that 1 is supplementary to 3 as follows:

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\begin{tabular}&#10;{|c|c|}&#10;\angle1\ is\ supplementary\ to\ \angle3&Deifinition of supplementary \angle s&#10;\end{tabular}</span>
3 0
3 years ago
Read 2 more answers
There are 18 bicycles. There are more more blue than yellow. There are 2 less yellow than green. How many of each color are ther
nasty-shy [4]
The are 8 blue bicycles, 6 green bicycles, and 4 yellow bicycles and total they equal 18.
5 0
3 years ago
If PQR is a triangle,given that /PQ\=15m, /QR\=17m and /RP\=18m.Find the area of the triangle to the nearest whole number.
nydimaria [60]

Answer:

118.3 m²

Step-by-step explanation:

Step 1. Calculate the <em>semiperimeter</em> (s).

s = (p + q + r)/2

s = (17 + 18+ 15)/2  

s = 50/2

s = 25 m

===============

Step 2. Calculate the <em>area</em> (A).

Use <em>Heron’s formula</em>:

A = \sqrt{s(s-p)(s-q)(s-r)}

A = \sqrt{25(25-17)(25-18)(25-15)}

A = \sqrt{25\times8\times7\times10}

A = \sqrt{14 000}

A = 20\sqrt{35}

A = 118.3 m²

3 0
3 years ago
Which sequence explains a geometric method of determining<br> 3 - 17i/2 +2i?
never [62]

Answer:

That would be D.

Step-by-step explanation:

first, turn both to polar form. Then you plot the first one and scale by the second. also, using a Rectangular to Polar calculator, we can see that 2.82 is 2 sqrt 2, so it cannot be A or B. It also can't be C since you graph 3-17i first.

7 0
3 years ago
Read 2 more answers
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