Putting the value of Y = 15
So, X = 200
Answer:
6.23% probability that the fourth part retrieved from stock is the first defective
Step-by-step explanation:
For each part, we have that:
8% probability of being defective.
100-8 = 92% probability of not being defective.
The parts are independent of each other.
What is the probability that the fourth part retrieved from stock is the first defective?
The first three work correctly, each one with a 92% probability.
The fourth is defective, with an 8% probability.
P = 0.92*0.92*0.92*0.08 = 0.0623
6.23% probability that the fourth part retrieved from stock is the first defective
Answer:
Take the slopes, such that 7-4/-4+3= 3/-1=-3
So one endpoijt is (-5,10)
11,850 x .9 = 11,605
11605 x . 9 = 9,598.5 year 2
9,598.5 x .9 = 8,638.65
8,635 x .9 = 7,774.785 year 4
7,774.785 x .9 = 6,997.31
6,6997.31 x .9 = 6297.58 year 6
6297.58 x .9 = 5,667.82
5,667.82 x .9 = 5,101.04 year 8
The answer is D
