Guadrilateral whose vertices are A(-2-2),B(5-2),C(4-3) and D(-3,-3)what kind of a guadrilatetal is ABCD?
1 answer:
Answer:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
The vertices of the quadrilateral ABCD are;
A(-2 -2), B(5, -2), C(4, -3)and D(-3, -3)
The slope of segment = (-2 - (-2))/(5 - (-2)) = 0
The length of segment = 5 - (-2) = 7 (points having the same y-coordinates)
The slope of segment = (-3 - (-2))/(-3 - (-2)) = 1
The length of segment = √((-3 - (-2))² + (-3 - (-2))²) = √2
The slope of segment = (-3 - (-3))/(-3 - 4) = 0
The length of segment = 4 - (-3) = 7 (points having the same y-coordinates)
The slope of segment = (-3 - (-2))/(4 - 5) = 1
The length of segment = √((4 - 5)² + (-3 - (-2))²) = √2
Therefore;
The opposite sites of the quadrilateral ABCD are equal; =
,
=
Given that the slope of a line gives the inclination of the line on a graph, we have;
The opposite sites of the quadrilateral are parallel; ║
,
║
Therefore the quadrilateral ABCD is a parallelogram because the opposite sides of the quadrilateral ABCD are parallel.
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