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3 years ago

9

Calculate the work done by a 47N force pushing a pencil 0.26m

1 answer:

erastovalidia [21]3 years ago

4 0

According to my examination I have confirmed that I do NOT repeat do NOT know this.

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What is your understanding of repetition and replication in science?

strojnjashka [21]

From my understanding, the two are opposite. Let me give you each word and what it scientifically means to me.

repetition
occurs when an activity is repeated by the same person

replication
occurs when an activity is repeated by a different person

I hope this completely answers your question! If you need further explanation, please let me know!
~Brooke❤️

5 0

3 years ago

Consider the free-body diagram. Assume there is a net force of 30N to the right and the friction force equals 20N. What is the a

oksano4ka [1.4K]

Answer:the answer would be C.50N

Explanation:I just took the test

6 0

4 years ago

ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is obs

inessss [21]

Answer:

Part a)

$m_2 = 4.9 \times 10^7 kg$

Part b)

$q_1 = q_2 = 5312.6 C$

Explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

$F = m_1a_1 = m_2a_2$

here we have

$6.3 \times 10^7(7) = m_2(9)$

now we have

$m_2 = 4.9 \times 10^7 kg$

Part b)

Now for the force between two charges we can say

$F = \frac{kq_1q_2}{r^2}$

now we have

$(6.3 \times 10^7)(7) = \frac{(9\times 10^9)q^2}{(24\times 10^3)^2}$

now we have

$q_1 = q_2 = 5312.6 C$

3 0

4 years ago

What is the formula for momentum?

Tems11 [23]

P=MV Is The Equation
Youre Welcome !

7 0

3 years ago

Read 2 more answers

A 31.0 kW electric motor drives a vehicle at an average velocity of 9.20 m/s. Assuming a constant force is applied in the direct

babunello [35]

The magnitude of the applied force is 3369.57 N.

<h3>What is Force?</h3>

Force can be defined as the product of mass and acceleration.

To calculate the magnitude of the applied force, we use the formula below.

Formula:

P = Fv................ Equation 1

Where:

P = Power of the electric motor
F = Applied force
v = Velocity

Make F the subject of the equation

F = P/v................. Equation 2

From the question.

Given:

P = 31 kW = 31000 W
v = 9.2 m/s

Substitute these values into equation 2

F = 31000/9.2
F = 3369.57 N

Hence, the magnitude of the applied force is 3369.57 N.

Learn more about force here: brainly.com/question/12970081

5 0

3 years ago