Given Information:
Current = Ii = 7.2 A
Number of turns inner coil = Ni = 140
Number of turns outer coil = No = 180
Radius inner coil = ri = 0.015 m
Radius outer coil = ro = 0.023 m
Required Information:
outer coil current = Io = ?
Answer:
Io = 8.6 A
Step-by-step explanation:
We have two coils, subscript i denotes inner coil and o denotes the outer coil.
According to the Biot-Savart Law
B = μ₀IN/2r
we will equate the inner and outer magnetic fields
Bi=Bo
μ₀IiNi/2ri = μ₀IoNo/2ro
μ₀ and 2 cancels out
Io = Ii*Ni*ro/No*ri
Io = 7.2*140*0.023/180*0.015
Io = 8.6 A
Therefore, a current of 8.6 A is needed to flow in opposite direction so that the magnetic field is opposite and the net magnetic field will be zero.
Answer:
Its new current will be 240.0milliAmps
Explanation:
According to ohms law,
V = IR
V is the supply voltage in a circuit
I is the current
R is the resistance
If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:
V1 = 120R1
R1 = V1/120...(1)
If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),
V2 = 2V1
V2 = IR2
2V1 = IR2
R2 = 2V1/I ... (2)
Since there are no changes in resistance
R1 = R2
Equating 1 and 2, we have:
V1/120 = 2V1/I
1/120 = 2/I
Cross multiplying
I = 2×120
I = 240milliAmps
Answer:
v = 10 m/s
Explanation:
Given,
Length of the vine, l = 36 m
Angle of inclination = 31.0◦ with the vertical
acceleration due to gravity = 9.81 m/s²
Using Conservation of energy
KE = PE
v = 10 m/s
Hence, the speed of the swing is equal to 10 m/s
Answer:
6926.4J
Explanation:
Given parameters:
Mass of iron = 200g
Initial temperature = 100°C
Final temperature = 22°C
Unknown:
Amount of heat transferred to the water = ?
Solution:
The quantity of heat transferred to the water is a function of mass and temperature of the iron;
H = m c Ф
m is the mass of the iron
Ф is the change in temperature
C is the specific heat capacity of iron = 0.444 J/g°C
Now;
insert the parameters and solve;
H = 200 x 0.444 x (100-22)
H = 6926.4J
The test charge used to determine the electric field is very, very small so that its presence does not affect the electrical field because of the supply price. The electrical rate that produces the electric area is known as a source charge.
An electric-powered area is a physical area that surrounds electrically charged debris and exerts pressure on all differently charged particles inside the area, both attracting or repelling them. It also refers back to the physical field for a machine of charged particles.
Electric-powered discipline is described as the electrical force in keeping with unit fee. The path of the sector is taken to be the route of the force it might exert on a fine check price. the electric discipline is radially outward from a nice rate and radially in toward a bad point rate.
An electric discipline is a vicinity of space around an electrically charged particle or object in which an electric charge might sense force. An electric field is a vector amount and may be visualized as arrows going in the direction of or away from fees.
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