Answer: i think the answer is 20.0s
Explanation:
Explanation:
It is given that,
Magnitude of charge, ![q=15\ \mu C=15\times 10^{-6}\ C](https://tex.z-dn.net/?f=q%3D15%5C%20%5Cmu%20C%3D15%5Ctimes%2010%5E%7B-6%7D%5C%20C)
It moves in northeast direction with a speed of 5 m/s, 25 degrees East of a magnetic field.
Magnetic field, ![B=0.08\ j](https://tex.z-dn.net/?f=B%3D0.08%5C%20j)
Velocity, ![v=(5\ cos25)i+(5\ sin25)j](https://tex.z-dn.net/?f=v%3D%285%5C%20cos25%29i%2B%285%5C%20sin25%29j)
![v=[(4.53)i+(2.11)j]\ m/s](https://tex.z-dn.net/?f=v%3D%5B%284.53%29i%2B%282.11%29j%5D%5C%20m%2Fs)
We need to find the magnitude of force on the charge. Magnetic force is given by :
![F=q(v\times B)](https://tex.z-dn.net/?f=F%3Dq%28v%5Ctimes%20B%29)
![F=15\times 10^{-6}[(4.53i+2.11j)\times 0.08\ j]](https://tex.z-dn.net/?f=F%3D15%5Ctimes%2010%5E%7B-6%7D%5B%284.53i%2B2.11j%29%5Ctimes%200.08%5C%20j%5D)
<em>Since</em>, ![i\times j=k\ and\ j\times j=0](https://tex.z-dn.net/?f=i%5Ctimes%20j%3Dk%5C%20and%5C%20j%5Ctimes%20j%3D0)
![F=15\times 10^{-6}[(4.53i)\times (0.08)\ j]](https://tex.z-dn.net/?f=F%3D15%5Ctimes%2010%5E%7B-6%7D%5B%284.53i%29%5Ctimes%20%280.08%29%5C%20j%5D)
![F=0.00000543\ kN](https://tex.z-dn.net/?f=F%3D0.00000543%5C%20kN)
![F=5.43\times 10^{-6}\ kN](https://tex.z-dn.net/?f=F%3D5.43%5Ctimes%2010%5E%7B-6%7D%5C%20kN)
So, the force acting on the charge is
and is moving in positive z axis. Hence, this is the required solution.
Answer:
563712.04903 Pa
Explanation:
m = Mass of material = 3.3 kg
r = Radius of sphere = 1.25 m
v = Volume of balloon = ![\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
M = Molar mass of helium = ![4.0026\times 10^{-3}\ kg/mol](https://tex.z-dn.net/?f=4.0026%5Ctimes%2010%5E%7B-3%7D%5C%20kg%2Fmol)
= Density of surrounding air = ![1.19\ kg/m^3](https://tex.z-dn.net/?f=1.19%5C%20kg%2Fm%5E3)
R = Gas constant = 8.314 J/mol K
T = Temperature = 345 K
Weight of balloon + Weight of helium = Weight of air displaced
![mg+m_{He}g=\rho vg\\\Rightarrow m_{He}=\rho vg-m\\\Rightarrow m_{He}=1.19\times \frac{4}{3}\pi 1.25^3-3.3\\\Rightarrow m_{He}=6.4356\ kg](https://tex.z-dn.net/?f=mg%2Bm_%7BHe%7Dg%3D%5Crho%20vg%5C%5C%5CRightarrow%20m_%7BHe%7D%3D%5Crho%20vg-m%5C%5C%5CRightarrow%20m_%7BHe%7D%3D1.19%5Ctimes%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%201.25%5E3-3.3%5C%5C%5CRightarrow%20m_%7BHe%7D%3D6.4356%5C%20kg)
Mass of helium is 6.4356 kg
Moles of helium
![n=\frac{m}{M}\\\Rightarrow n=\frac{6.4356}{4.0026\times 10^{-3}}\\\Rightarrow n=1607.85489](https://tex.z-dn.net/?f=n%3D%5Cfrac%7Bm%7D%7BM%7D%5C%5C%5CRightarrow%20n%3D%5Cfrac%7B6.4356%7D%7B4.0026%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5CRightarrow%20n%3D1607.85489)
Ideal gas law
![P=\frac{nRT}{v}\\\Rightarrow P=\frac{1607.85489\times 8.314\times 345}{\frac{4}{3}\pi 1.25^3}\\\Rightarrow P=563712.04903\ Pa](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BnRT%7D%7Bv%7D%5C%5C%5CRightarrow%20P%3D%5Cfrac%7B1607.85489%5Ctimes%208.314%5Ctimes%20345%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%201.25%5E3%7D%5C%5C%5CRightarrow%20P%3D563712.04903%5C%20Pa)
The absolute pressure of the Helium gas is 563712.04903 Pa
Rank of the radiation particles according to their ability to penetrate solid objects, from the best able to penetrate to the least able to penetrate:
C ) gamma particle, beta particle, alpha particle.
Answer: certificate authority
Explanation: The user submits Identification data and certificate request to the registration authority (RA). The RA validates this information and sends the certificate request to the certificate Authority (CA)