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3 years ago

What the Ph measures??

1 answer:

5 0

PH measures the concentration of hydrogen ions ( $H^{+}$ ) in a solution. Knowing this, you can determine how acidic -or basic- your solution is.

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This is the portion of the electromagnetic spectrum that has a frequency just below the visible spectrum.

Hatshy [7]

Answer: Radiowaves, infrared radiations.

Explanation:

First things first, the electromagnetic spectrum is an array of radiations which result from the interference of an electric and magnetic component.

The portion of the electromagnetic spectrum which can be seen using the eye is termed the visible spectrum.

This visible spectrum have a range of wavelengths with lower limit of 380 nm and an upper limit of 740nm.

The electromagnetic radiations that have a frequency below the visible spectrum are Radio waves which may be microwaves in their highest frequency forms and also we have the infrared radiation.

6 0

4 years ago

Read 2 more answers

How are magnetic force and distance from an object related

guapka [62]

Answer:

Magnetic force obeys an inverse square law with distance

Explanation:

6 0

3 years ago

Read 2 more answers

In which of these cases is NO work done on the football? A) You lift a football off the ground. B) You raise a football over you

inn [45]

I believe the answer is C.

8 0

3 years ago

If the space station is 190 m in diameter, what angular velocity would produce an "artificial gravity" of 9.80 m/s2 at the rim?

ozzi

Answer:

The angular velocity produced is 0.321 rad/s.

Explanation:

Given :

Diameter of space station , D = 190 m.

Therefore, radius , $R=\dfrac{D}{2}=\dfrac{190}{2}=95\ m.$

Also, acceleration , $a=9.8\ m/s^2.$

We know, angular velocity , $\omega=\sqrt \dfrac{a}{R}$ .

Putting value of g and R in above equation.

We get ,

$\omega=\sqrt \dfrac{9.8\ m/s^2}{95\ m}$

$\omega=0.321\ rad/s.$

Hence, this is the required solution.

6 0

4 years ago

A satellite has a mass of 5850 kg and is in a circular orbit 4.1 x10 to the 5th power m above the surface of a planet. The perio

koban [17]

Answer:

W = 24.28 kN

Explanation:

given,

Mass of satellite = 5850 Kg

height , h = 4.1 x 10⁵ m

Radius of planet = 4.15 x 10⁶ m

Time period = 2 h

= 2 x 3600 = 7200 s

Time period of satellite

$T = \dfrac{2\pi}{R}\sqrt{\dfrac{(R+h)^3}{g}}$

R is the radius of planet

h is the height of satellite

$T^2 = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{g}}$

now calculation of acceleration due to gravity

$g = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{T^2}}$

$g = \dfrac{4\pi^2}{(4.15\times 10^6)^2}\ {\dfrac{(4.15\times 10^6+4.1\times 10^5)^3}{(7200)^2}}$

g = 4.15 m/s²

True weight of satellite

W = m g

W = 5850 x 4.15

W = 24277.5 N

W = 24.28 kN

True weight of the satellite is W = 24.28 kN

8 0

3 years ago