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Juliette [100K]
3 years ago
12

Use OZ with VW – XY What is XY ? A 30 B. 35 C. 40 D 50

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

40

Step-by-step explanation:

From the diagram;

VW = 2(20)

VW = 40

Simce VW is similar to XY, hence VW = XY = 40

Hence the length of XY is 40

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Teniendo en cuenta que tg 45°=1, deduce el valor de sen 45° y de cos 45° mediante las relaciones fundamentales.
Nana76 [90]

Answer:

the value is 0.707

Step-by-step explanation:

The computation is shown below:

Tan (x) = sen (x) ÷ cos (x)

Tan 45° = sen 45° ÷ cos 45° = 1

Now

Sen^2 (x) + cos^2 (x) = 1

Sen^2 (x) + sin^2 (x) = 1 (As sen (x) = u)

2u^2 = 1

u = √1 ÷ √2

= √2 ÷ 2

= 0.707

Hence, the value is 0.707

6 0
3 years ago
All graphs need to have a key, the data (imformation) and a _____?
jarptica [38.1K]

Answer:

B

Step-by-step explanation:

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3 years ago
50 POINTS 10 QUESTIONS! <br><br> Solve each quadratic equation using factoring<br><br> PLEASE HELP!!
Tanzania [10]

Answer:

Quadratic Equation | Factoring

Solve each quadratic equation using factoring.

1) v² + 5v + 6 = 0

doing middle term factorisation

v²+(3+2)v+6=0

v²+3v+2v+6=0

v(v+3)+2(v+3)=0

(v+3)(v+2)=0

either

<u>v=-3</u>

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<u>v=-2</u>

2) g² - 3g = 4

keeping all terms in one side

g²-3g-4=0

doing middle term factorisation

g²-(4-1)g-4=0

g²-4g+g-4=0

g(g-4)+1(g-4)=0

(g-4)(g+1)=0

either

<u>g=4</u>

<u>or</u>

<u>g=-1</u>

3)w² + 4w = 0

w(w+4)=0

either

<u>w=0</u>

<u>or</u>

<u>w=-4</u>

4) s² - 8s + 12 = 0

doing middle term factorisation

s²-(6+2)+12=0

s²-6s-2s+12=0

s(s-6)-2(s-6)=0

(s-6)(s-2)=0

either

<u>s=6</u>

<u>or</u>

<u>s=2</u>

5) x ²+ 2x - 35 = 0

doing middle term factorisation

x²+(7-5)x-35=0

x²+7x-5x-35=0

x(x+7)-5(x+7)=0

(x+7)(x-5)=0

either

<u>x=-7</u>

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6) r(r + 2) = 99

opening bracket

r²+2r=99

keeping all terms in one side

r²+2r-99=0

r²+(11-9)r-99=0

r²+11r-9r-99=0

r(r+11)-9(r+11)=0

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<u>r=-11</u>

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7)k(k-4)=-3

opening bracket

k²-4k=-3

keeping all terms in one side

k²-4k+3=0

k²-(3+1)k+3=0

k²-3k-k+3=0

k(k-3)-1(k-3)=0

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either

k=3

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k=1

8)t²+ 3t + 2 = 0

doing middle term factorisation

t²+(2+1)t+2=0

t²+2t+t+2=0

t(t+2)+1(t+2)=0

(t+2)(t+1)=0

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<u>t</u><u>=</u><u>-</u><u>2</u>

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9)m ^ 2 - 81 = 0

m²=81

doing square root in both side

\sqrt{m²}=\sqrt{9²}

<u>m=±9</u>

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<u>m</u><u>=</u><u>9</u>

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10) h²- 17h + 70 = 0

doing middle term factorisation

h²-(10+7)h+70=0

h²-10h-7h+70=0

h(h-10)-7(h-10)=0

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<u>h</u><u>=</u><u>1</u><u>0</u>

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6 0
2 years ago
Read 2 more answers
I need help to solve this question.
LekaFEV [45]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
What are the last 2 digits of 7 to the power of 2018. This question was on a past exam paper.
Xelga [282]

Answer:

49

Step-by-step explanation:

  • Try finding pattern of last two digits of 7 to the power of some numbers.

7^1=07

7^2=49

7^3=343

7^4= 2301

7^5= 16807

  • so , the pattern is, 07,49,43,01
  • so, if we start writing all numbers from 1 to 2018 , four number in each line, 2018 will fall in the second column.
  • so it will have 49 as the  last 2 digits [by seeing this pattern : 07,49,43,01 ]
6 0
2 years ago
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