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olga nikolaevna [1]
3 years ago
5

Can someone find the points/coordinates of this graph?

Mathematics
1 answer:
BigorU [14]3 years ago
4 0

Answer:

The x represents the value of the point on the x axis or the horizontal line, and the y represents the vertical line. Now, lets solve for the first point. We can first see that it only moves to the left by two from zero, which is basically -2. So, right now we have (-2,y). We then look for the y in which we see that it is down -6 from zero, so it will be (-2,-6). Time to look for the second point. We should get (2,-3). Now, with these two points, it is time to find the slope intercept form.  

Step-by-step explanation:

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One hundred and three twenty four thousandths
Brrunno [24]
I think it is .1324 but I need a little more details.
3 0
3 years ago
PLZ HELP DUE AT 12
aleksandrvk [35]

Answer:

The first one would be m^30n^20p^30  

And the second one would be a^2 / d^4  

Step-by-step explanation:

For 1, you have to multiply the inner exponents by the outer one so you get (m^12n^8) times (m^18n^12p^30). Then you mutiply the two together, so you add the exponents, where you get m^30n^20p^30.

For 2, since you're dividing, you have to subtract the exponents so you get a^2d^-4, but since you shouldn't have the negative you turn it into a^2 / d^4

Hope this helps :)

4 0
3 years ago
Plot four lines. Each line should pass through the point
notka56 [123]

Answer:

Step-by-step explanation:

I am on the same question

3 0
3 years ago
What is the additive inverse of the complex number –8 + 3i?
Lady bird [3.3K]
Choices:
–8 – 3i
–8 + 3i
8 – 3i
<span>8 + 3i

The additive inverse of the complex number a + bi is -(a+bi) = -a - bi

In this case, a = -8 and b = 3i

a + bi = -8 + 3i
additive inverse is:  -(-8+3i) = +8 - 3i

The additive inverse of the complex number -8 + 3i is 8 - 3i. The 3rd choice.


</span>
5 0
3 years ago
Read 2 more answers
Someone please help me with this.
svetlana [45]

Answer:

9

Step-by-step explanation:

m = j^2 -7p

18 = j^2 -7(9)

18 = j^2 - 63

81 = j^2

√81 = √j^2

9 = j

6 0
3 years ago
Read 2 more answers
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