Question

Find the Pythagorean Triple (a,b,c) using the terms (x²-1, 2x, x²+1) for x > 0 when x =7.

Answer 1

1) 7^2-1=48
2x7=14
7^2+1=50
=(48,14,50)
2)10^2-6^2=64
2x10x6=120
10^2+6^2=136
=(64,120,136)