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Julli [10]
3 years ago
6

If no mechanical energy were lost, a skateboarder descending a straight 40 meter slope would arrive at its foot with speed of 15

m/s.Calculate the angle the slope makes with the horizontal​
Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

Answer

Step-by-step explanation:

Step-by-step explanation

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What is the slope of a line with the eqation of 4×+5y=5
evablogger [386]

Answer:

- 4/5x

Step-by-step explanation:

So, this is a simple thing as long as you convert it into slope-int form. So, I am guessing from the question that the equation is

4x + 5y = 5

From here, you have to isolate y and leave all of the other variable by themselves. So, first you would subtract 4x from both sides and that leaves you with

5y = 5 -4x

Then, to isolate 5, you would divide 5 by both sides to get

y = 1- 4/5x

Now, you would put this is slope intercept form: y = mx + b to get

y = - 4/5 x + 1

Now, you can see that the slope is - 4/5x

Hope I helped!!!!!

6 0
3 years ago
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Which eqaution dosen't belong
kompoz [17]

Answer:

you need more info please

Step-by-step explanation:

8 0
3 years ago
A triangle with 118° and 42 in. is what type of triangle?
tankabanditka [31]
<span>If the triangle has an obtuse angle (>90 degrees), it can be classified as an obtuse triangle Not sure where the 42 inches is used Hope this helps</span>
3 0
4 years ago
Read 2 more answers
10-
Blababa [14]

Answer:

x = 2

Step-by-step explanation:

This blue line seems to be horizontal, and so a line perpendicular would have to be vertical. The only vertical line that passes through (2, 6) would be x = 2.

5 0
3 years ago
The area of a triangle is 15x^4+3x^3+4x^2-x-3 square meters. The length of the base of the triangle is 6x^2-2 meters. What is th
MArishka [77]

Answer:

The height of the triangle is: H = (5x^2 + x +3)

Step-by-step explanation:

Here, the area the triangle  is given as: 15x^4 + 3x^3 + 4x^2 - x  - 3

Also, base of the triangle  = (6x^2 -2)

Let us assume the height of the triangle = H units

Now, AREA of TRIANGLE =  \frac{1}{2}  \times B  \times H

\implies (15x^4+3x^3+4x^2-x-3 ) = \frac{1}{2}  \times ( 6x^2-2)  \times H\\\implies H =\frac{ (15x^4+3x^3+4x^2-x-3 )}{(3x^2-1)}

Solving by LONG DIVISION, we get:

H = (5x^2 + x +3)

Hence, the height of the triangle is: H = (5x^2 + x +3)

6 0
3 years ago
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