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amm1812
3 years ago
14

Suppose that the radius of a circle increases at a constant rate of 0.25 cm/sec. When the radius of this circle is 16 cm, the ar

ea of the circle increases at a rate of
Mathematics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

8πcm²/sec

Step-by-step explanation:

The radius of the circle increases at a rate of dr/dt = 0.25cm/sec

The radius of the circle r = 16cm

The area of the circle increases at a rate of dA/dt = ?

Area of a circle = πr²

We take the derivative with respect to t

dA/dt = 2πrdr/dt

dA/dt = 2 π (16)(0.25)

dA/dt = 8πcm²/sec

Thank you!!!

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Answer:

x = -5

Step-by-step explanation:

Since these two triangles are similar, the ratio between the corresponding lengths of each triangle will be the same.

This means the ratio between one side of each triangle (e.g. AD and DC) will be the same as the ratio between a different side of each triangle (e.g. BE and BC).

So, to create an equation for the sides which contain the unknown 'x', we must first find the ratio between the two sides by using a different set of sides.

On the right side we are given 9 for AD, and 18 for DC.

9/18 = 0.5

This means that the extra length of the larger triangle from the smaller one (AD) is half the length of the smaller triangle (DC). We can use this to make an equation for x:

If AD/DC = 0.5, then BE/EC will also = 0.5

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Therefore:

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Now we can solve by multiplying both sides by x+41 to eliminate the fraction:

x+23=0.5(x+41)

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We will see that -5 does indeed give us the same ratio between the lengths:

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Hope this helped!

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