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amm1812
3 years ago
14

Suppose that the radius of a circle increases at a constant rate of 0.25 cm/sec. When the radius of this circle is 16 cm, the ar

ea of the circle increases at a rate of
Mathematics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

8πcm²/sec

Step-by-step explanation:

The radius of the circle increases at a rate of dr/dt = 0.25cm/sec

The radius of the circle r = 16cm

The area of the circle increases at a rate of dA/dt = ?

Area of a circle = πr²

We take the derivative with respect to t

dA/dt = 2πrdr/dt

dA/dt = 2 π (16)(0.25)

dA/dt = 8πcm²/sec

Thank you!!!

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The answer to you question is 74.
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3 years ago
The volume of a cube is 460cm3.<br> Work out the length of its side rounded to 1 DP.
yaroslaw [1]
The side length is the cube root of 460.

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7 0
3 years ago
Which is greater, 13/35 or 2/5?
zhenek [66]
Hi there!

If you run into problems like this, remember to "Stay calm and find the common denom." That just means find the common denominator.

13/35 and 2/5 = 13/35 and 14/35

As you can tell, 2/5 is larger.

Hope this helps.

:)
5 0
3 years ago
g The manager of a grocery store has selected a random sample of 100 customers. The average length of time it took these 100 cus
vagabundo [1.1K]

Answer:

The right solution is "0.196".

Step-by-step explanation:

The given values are:

Standard deviation,

\sigma=1 \ minute

Sample size,

n=100

Confidence level,

c=95%

  =0.95

Now,

For \alpha=1-c

         = 1-0.95

         =0.05

then,

Z_{\frac{\alpha}{2} } = Z_{\frac{0.05}{2} }

     =Z_{0.025}

     =1.96

The margin or error will be:

⇒ E=Z_{\frac{\alpha}{2} } (\frac{\sigma}{\sqrt{n} })

On substituting the values, we get

       = 1.96(\frac{1}{\sqrt{100} })

       = 1.96\times \frac{1}{10}

       = 0.196

7 0
2 years ago
Please help!! 10-|-5-2|
Lena [83]

Answer:

3

Step-by-step explanation:

10-|-5-2|

10-|-7|

10-(7)

10-7

3

5 0
3 years ago
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