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Brums [2.3K]
3 years ago
14

An MP3 player costs $70 and song downloads cost $0.95 each. Write an expression that represents the cost of the MP3 player and x

number of song downloads
Mathematics
1 answer:
babunello [35]3 years ago
3 0
Let x represent the number of song downloads and let y represent the total cost

y=0.95x+70
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Lana has 3 bags with the same amount of marbles in them, totaling 12 marbles. Markus has 3 bags with the same amount of marbles
Julli [10]

Answer:

Markus has 6 marbles in each bag.

Step-by-step explanation:

Markus has 18 marbles and 3 bags

If you divide 18 marbles by 3 bags that would be 6 marbles in each bag.

5 0
3 years ago
1 Point
I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

7 0
3 years ago
Will mark brainliest! Answer quickly please.
inn [45]
1400kg.
Force=ma
2100N= m*1.5
2100/1.5= 1400kg.
Please mark me brainliest :)
3 0
2 years ago
For nitrogen to be a liquid, its temperature must be within 12.78 °F of –333.22 °F. Which equation can be used to find the maxim
ziro4ka [17]
To determine the maximum and minimum temperatures at which nitrogen remains a liquid, use the equation |x - (-333.32)| = 12.78, where x is equal to the maximum and minimum temperatures. Using this equation, the maximum temperature is -320.54 degrees Fahrenheit while the minimum is -346.10 degrees Fahrenheit.
3 0
3 years ago
Read 2 more answers
Please help I will give brainliest or thanks please help me
Dovator [93]
15 minutes= 2 problems
75 / 15 = 5
2 x 5 = 10 problems
7 0
3 years ago
Read 2 more answers
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