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Dima020 [189]
3 years ago
10

What is 17 1/5 x 7 3/4

Mathematics
1 answer:
irina1246 [14]3 years ago
4 0
17+7 =25
1/5 = 0.20
3/4= 0.75

25 + 0.20 + 0.75
=25 + 0.95
= 25.95
I hope this helped a bit!:)
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Brenda invests $4,848 in a savings account with a fix annual interest rate of 5% compounded 2 times per year.what will the accou
Mashutka [201]

A = P(1 + rt)

A= 4,848(1+.05*6)

A=6302.4

7 0
3 years ago
Use the formula for computing future value using compound interest to determine the value of an account at the end of 6 years if
nadezda [96]

Answer: the value of the account at the end of 6 years is is $8577

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 6000

r = 6% = 6/100 = 0.06

n = 4 because it was compounded 4 times in a year.

t = 6 years

Therefore,.

A = 6000(1+0.06/4)^4 × 6

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5 0
3 years ago
Help me please :)))))​
vodomira [7]

Answer:

a number. 5. b number. 7 fourth one. c number. 1. d number 0

Step-by-step explanation:

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7 0
2 years ago
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JK and LM are straight lines. Find /NOK.<br> ( help me pls)<br>​
VashaNatasha [74]

Answer:

NOK = 58

Step-by-step explanation:

Given

JOM = 108

LON = 50

Required

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From the attached triangle, we have:

LOK = JOM =108 --- Corresponding angles

And

LOK = LON + NOK

Substitute for LOK and LON

108= 50+ NOK

Make NOK the subject

NOK = 108 - 50

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8 0
3 years ago
A 6 foot tall football player casts a 16 inch shadow at the same time stadium we discussed at six for shadow how tall the bleach
katrin [286]
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.

6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.

So the bleachers are 9/2 x 6 ft = 27 ft.

For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.

So the stage will have dimensions 216 times larger than 1.75" by 3".

That would be 31ft 6ins x 54ft.

Live long and prosper.
5 0
3 years ago
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