3 years ago

What is 17 1/5 x 7 3/4

Mathematics

1 answer:

irina1246 [14]3 years ago

4 0

17+7 =25
1/5 = 0.20
3/4= 0.75

25 + 0.20 + 0.75
=25 + 0.95
= 25.95
I hope this helped a bit!:)

You might be interested in

A boat is traveling at an average speed of 15 meters per second. How many kilometers per second is the boat traveling

damaskus [11]

$15 \frac{m}{s} \to 15\frac{10^{-3} km}{s} \to\boxed{0.015 \frac{km}{s}}$

8 0

3 years ago

Read 2 more answers

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

3 years ago

10. Jessica had dance class for 3 hours last night, Tiffany had dance class for of time that Jessica had dance class. How long d

Stolb23 [73]

Answer:

i think theres a typo somewhere

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Dan invests £6800 into his bank account. He receives 5% per year compound interest. How much will Dan have after six years? Give

tia_tia [17]

Answer:

£6800 times (1.05)to the power of 6

=£9112.65

Step-by-step explanation:

5 0

2 years ago

Help please ........

Nitella [24]

Answer:

Step-by-step explanation:

eh too lazy to explain but plz trust me

5 0

3 years ago