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user100 [1]
3 years ago
5

Easy algebra question below first correct answer

Mathematics
1 answer:
grin007 [14]3 years ago
6 0

area = x^2 - 4x + 3

...................................

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How many times greater is 10 cubic yards than 5 cubic yard? Complete the equation
monitta

Answer:

2 times

Step-by-step explanation:

10 / 5 = 2

   or

5 x 2 = 10

so 10 is 2 times greater than 5

8 0
3 years ago
The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an
Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w  feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = \dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, w = \dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}

Or, w = \dfrac{-11\pm \sqrt{473}}{2}

or, w = \dfrac{-11\pm 21.7}{2}

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

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3 years ago
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The total is 28+.6/28.....
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Use substitution to solve the system of equations.<br> y=-4x+11<br> 3x+y=9
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Answer:

(2,3)

Step-by-step explanation:

(Brainliest please)

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2 years ago
Write the number 119,000,003 in two other forms
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One hundred million and three dollars
100,000,000+10,000,000,+9,000,000+3
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