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2 years ago

I am a number between 60 and 100 my digit is two more than my tens digit I am a prime number what number am I

Mathematics

2 answers:

frez [133]2 years ago

8 0

Answer:

It is 79

Step-by-step explanation:

9-7 is 2

almond37 [142]2 years ago

5 0

Answer:

Step-by-step explanation:

x has to be more than 60 and less than 100

the primes between those are 61,67,71,73,79,83, 89, 97

97 is two less in the ones than in the tens so it completes all of the requirements of the riddles therefore, 97 is the answer.

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What would 5.36 be in a fraction<br> Please explain how you got the answer too.

garri49 [273]

So you have 5.36
that is 5 wholes and 0.36
0.36 can be written on a fraction of 36/100
simplify it to 9/25
Now you have the mixed number
5 9/25 or to write it into an improper fraction... multiply 25 * 5 then add 9, that is 134/25.

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2 years ago

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What is 10 more than 451

snow_lady [41]

<span>To find 10 more than 451 is very simple, simply add 10 to 451 to get 461.</span>

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3 years ago

Calculate the angle of depression from the

Verizon [17]

Answer: $52.6^{\circ}$

Step-by-step explanation:

Let the angle of depression be x.

$\sin x=\frac{27}{34}\\\\x=\sin^{-1} \left(\frac{27}{34} \right) \approx 52.6^{\circ}$

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1 year ago

Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp

Maslowich

If $p(3-2i)=0,$ then complex number $3-2i$ is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated $3+2i$ is also a root of polynomial.

Then the polynomial will be of a form

$p(x)=(x-(3-2i))(x-(3+2i))(x-a).$

Since $p(0)=-52,$ then

$-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.$

Therefore,

$p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.$

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2 years ago

I need hlep on Number 2 ?and number 1 ?

Nimfa-mama [501]

1. 20 slices

2. 54 for herself

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2 years ago

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