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Delvig [45]
3 years ago
9

What is 5x4? will give brainliest

Mathematics
2 answers:
KiRa [710]3 years ago
7 0

Answer:

20

Step-by-step explanation:

5 10 15 20

Kay [80]3 years ago
4 0
It is 20 I’m pretty sure !
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Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 3.
Svetllana [295]
f(x)=\log_{10}x \\ 10^y=3 \\ y=\log_{10}3=0.4771
3 0
3 years ago
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PLEASE HELPPP, its timed. NO BOTS please i want serious answers.
Rzqust [24]
CDAB

4.2 (convert to frac on ur own)

12.5=x

CB= 14.5

AB= 8.82
6 0
2 years ago
Which of the following is NOT true about the following equation. y= -4​
Alex Ar [27]

Answer:

Answer is D.

Step-by-step explanation:

Which is not true?

So, lets assess the answers given to the question.

A. It is the equation of a horizontal line.

Yes, it is. Since there is only one y - value which is y = -4, we can confirm this is the y intercept, so therefore the x value is zero. But it's not the answer we're looking for.

B. It's slope is zero, yes the slope is zero. It only lists the y-intercept which confirms that the slope is 0.

C. Yes, I mean i can't really explain how. Just use desmos calculator, the graph is exactly perpendicular.

D. The line actually does cross the x-axis, -4 is the y intercept and the x value is 0, and zero is still a point. So D is the one which isn't correct making it the correct answer.

6 0
3 years ago
These roots of the polynomial equation x^4-4x^3-2x^2+12x+9=0 are 3,-1,-1. Explain why the fourth root must be a real number. Fin
Alex787 [66]

Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.

Because we know 3 and -1 (multiplicity 2) are both roots, the last root r is such that we can write

x^4-4x^3-2x^2+12x+9=(x-3)(x+1)^2(x-r)

There are a few ways we can go about finding r, but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be (-3)(1)(1)(-r)=3r.

Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have

3r=9\implies r=3

so the missing root is 3.

Other things we could have tried that spring to mind:

- three rounds of division, dividing the quartic polynomial by (x-3), then by (x+1) twice, and noting that the remainder upon each division should be 0

- rational root theorem

4 0
3 years ago
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Please help it’s due today at 6:10am please help me please please need help please
zepelin [54]

Answer:

Step-by-step explanation:

a. 3-4x=-7-4x

3=-7. no solution

b. 15 - 2x = -7x

15 = -5x

x=-3. one solution

c. 7y-21=6y-21

y=0

1. -3x+4=-3x+7

4=7

2. 10+2x = 5x+2

8=3x

x=3/8

3. x+5=x+5

8 0
3 years ago
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