Max used a base ten blocks to solve the division problem 9.15 divided by 3.

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

6 0

Answer:

D 3 ones, 0 tenths, 5 hundredths

Step-by-step explanation:

9.15 divided by 3.

915/3 = 305

Then, moving the decimal point two units to the left, we have 3.05.

The last number before the decimal point is called ones, which means that we have 3 ones.

The first number after the decimal point is called tenths, which means that we have 0 tenths.

The second number after the decimal point is called hundredths, which means that we have 5 hundredths.

The correct answer is given by option D.

You might be interested in

If m angle 2 =70, find m angle 6

rusak2 [61]

m angle 6= 210

I'm not sure about this question

5 0

2 years ago

HELP! DUE IN A FEW HOURS

Alenkasestr [34]

Answer:

Options (C) and (E).

Step-by-step explanation:

Rotation is a rigid transformation in which size and shape of the figure and image remains the same.

That means angles and sides of the triangles given in the figure will remain same after the transformations given.

Since, the given triangle has been rotated about a point Z, each rotation will share the vertex Z.

And every figure is the transformed form of the given triangle, all four triangles will be congruent.

Options (C) and (E) are the correct options.

4 0

3 years ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.