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Marrrta [24]
3 years ago
14

find the smallest number which must be added to 2300 so that it becomes a perfect square (please dont spam for points or i will

report you.)
Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

4

Step-by-step explanation:

2300+4 = (48)^2

it's  a perfect square now

hope it helps

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Kenny reads 5/8 page in 2/3 minute. <br><br> This is unit rates
Nat2105 [25]
Find unit rate of pages read per minute:

(5/8)/(2/3)

(5/8)*(3/2)

(5*3)/(8*2)

(15)/(16)

15/16

Kenny reads 15/16 pages every minute (unit rate)
5 0
3 years ago
What times what equals -60 but also adds up to 17?
natulia [17]

20 and -3.

20*-3=-60

20+-3=17

5 0
4 years ago
Sherry has taken 10 quizzes. Her combined total for the 10 quizzes is 83 points. Nine of her quiz scores are shown on the plot.
castortr0y [4]

Answer:

9

Step-by-step explanation:

4 0
4 years ago
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Rebekah wants to read a certain number of pages each day during summer vacation. Today she reads 204 pages, which is 136% of her
ZanzabumX [31]
Rule of three
Pages        %
204     → 136%
x         → 100% (her goal)

x=204*100%/136%
x=150 pages

Answer: Rebeca wants to read 150 pages each day        
6 0
3 years ago
Read 2 more answers
I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
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