Answer:
299.99 miles
Step-by-step explanation:
Since the plane traveled due west,
The total angle is 49.17 + 90
Represent that with θ
θ = 49.17 + 90
θ = 139.17.
Represent the sides as
A = 170
B = 150
C = unknown
Since, θ is opposite side C, side C can be calculated using cosine formula as;
C² = A² + B² - 2ABCosθ
Substitute values for A, B and θ
C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17
C² = 22500 + 28900 - 51000 * Cos 139.17
C² = 51400 - 51000 (−0.7567)
C² = 51400 + 38,591.7
C² = 89,991.7
Take Square Root of both sides
C = 299.9861663477167
C = 299.99 miles (Approximated)
Hence, the distance between the plane and the airport is 299.99 miles
Answer:
For systolic pressure data:

For diastolic pressure data:

Systolic pressure is slightly less variable, among individuals in the sample, than diastolic pressure.
Step-by-step explanation:
The coefficient of variation is defined as the percentage relative variation of a set of data with respect to its average. And it is calculated like this:



For systolic pressure data:

For diastolic pressure data:

It is observed that the systolic pressure shows greater standard deviation but less coefficient of variation. This is due to the greater magnitude of its measurement scale.
Systolic pressure is slightly less variable, among individuals in the sample, than diastolic pressure.
You could have half a cookie, divide it into thirds. (a semi circle cut into thirds)
Answer:
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Step-by-step explanation:
The answer is A because if we stare with (-1,3) and go up by 1x, since the slope is 2, then 3 + 2 is 5 and we have (0,5). Hope this helps!