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Gekata [30.6K]
3 years ago
14

The lunch room at Diane’s school has a perimeter of 300 feet. The length of the room is 85 feet. What is the width of the room?

Mathematics
2 answers:
Bingel [31]3 years ago
7 0
Answer:65

Explanation:
P=L+W+L+W
300= total
L=85
85 x 2=170
300-170=130
130/2=65
Mumz [18]3 years ago
3 0

Answer:

65

Step-by-step explanation:

2w+ 2l = 300

2w + 170=300

2w= 130

w=65

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This graph shows the solution to which inequality?
sweet [91]

The graph shows the solution to inequality is; y > ¹/₃x - 2

<h3>How to interpret Inequality Graphs?</h3>

From the given graph, we see that the line joining the two dotted coordinates is a dashed line and as such the inequality will be less than or greater than.

Now, If a line passing through two points, then the equation of line is;

y - y1 = [(y2 - y1)/(x2 - x1)](x - x1)

Using the two given coordinates, we have;

y - (-3) = [(-1 - (-3))/(3 - (-3))](x - (-3))

y + 3 = (2/6)(x + 3)

y = ¹/₃x - 2

Since the related line is dashed and the shaded region is above the line, therefore the sign of inequality is >.

The graph shows the solution to inequality is;

y > ¹/₃x - 2

Read more about Inequality Graphs at; brainly.com/question/11234618

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7 0
2 years ago
Use the original price and the markup to find the retail price. Original price: $64; Markup: 20%
Leni [432]

Answer:

$76.80

Step-by-step explanation:

When a product has a certain markup, you need to multiply the markup by the price of the product, and then add that to the original price of the product. 20%=0.2, and 0.2*64=12.8. Adding this to the original price, you get 64+12.8=$76.80. Hope this helps!

8 0
3 years ago
Read 2 more answers
2.07)Solve for H: A = L ⋅ W ⋅ H
saw5 [17]
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7 0
3 years ago
the diameters of Douglas firs grown at a Christmas tree farm are normally distributed with a mean of 4 inches and a standard dev
aksik [14]

Answer:

Proportion of the trees will have diameters between 2 and 6 inches = 0.8164

Step-by-step explanation:

Given -

Mean (\nu )  = 4

Standard deviation (\sigma  ) = 1.5

Let X be the diameter of tree

proportion of the trees will have diameters between 2 and 6 inches =

P(2<  X<  6)   =  P(\frac{2 - 4 }{1.5}< \frac{X - \nu }{\sigma}<  \frac{6 - 4 }{1.5})

                         = P(\frac{-2 }{1.5}< Z<  \frac{2 }{1.5})     Put  [Z = \frac{X - \nu }{\sigma}]

                         =  P(-1.33< Z<  1.33)

                          = (Z<  1.33) - (Z<  -1.33)

                          = .9082 - .0918

                           = 0.8164

6 0
3 years ago
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