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3 years ago

Solve each system of equations using substitution. a=5b+8 a=-10b-7

Mathematics

1 answer:

lianna [129]3 years ago

7 0

Answer:

a = 3, b = -1

Step-by-step explanation:

a = 5b + 8

a = -10b - 7

5b + 8 = -10b - 7

Add 10b from both sides;

15b + 8 = -7

Subtract 8 from both sides;

15b = -15

Divide both sides by 15;

b = -1

Lets substitute b;

a = 5b + 8

a = 5(-1) + 8

a = -5 + 8

a = 3

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Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, the

Kazeer [188]

Answer:

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Step-by-step explanation:

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$m=\frac{3-6}{12-\left(-6\right)}$

$m=-\frac{1}{6}$

As the equation in point-slope form

$y-y_1=m\left(x-x_1\right)$

Here:

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using $m=-\frac{1}{6}$ and $\left(x_1,\:y_1\right)=\left(-6,\:6\right)$ then

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$-\frac{1}{6}\left(x-\left(-6\right)\right)=y-6$

$\mathrm{Multiply\:both\:sides\:by\:}-6$

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$x-30=-6y$

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$y=\frac{-1}{6}x+5$

Thus

$y=\frac{-1}{6}x+5$

comparing the equation with the slope-intercept form

$y=mx+b$

so,

$y=mx+b$

$y=\frac{-1}{6}x+5$

Therefore,

$m=-\frac{1}{6}$

$b=5$

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Solve each system of equations using substitution. a=5b+8 a=-10b-7​

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