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juin [17]
3 years ago
9

Solve each system of equations using substitution. a=5b+8 a=-10b-7​

Mathematics
1 answer:
lianna [129]3 years ago
7 0

Answer:

a = 3, b = -1

Step-by-step explanation:

a = 5b + 8

a = -10b - 7

5b + 8 = -10b - 7

Add 10b from both sides;

15b + 8 = -7

Subtract 8 from both sides;

15b = -15

Divide both sides by 15;

b = -1

Lets substitute b;

a = 5b + 8

a = 5(-1) + 8

a = -5 + 8

a = 3

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Select the correct answer from each drop-down menu. Quadrilateral PQRS, with vertex P(-5, -3), undergoes a transformation to for
anygoal [31]

Answer:

i) A. 180º rotation about the origin, ii) Q' = (4, 5).

Step-by-step explanation:

i) In this case, we understand that vertex P = (-5,-3) changed to P' = (5,3) after doing an operation. At first we must calculate the distance of each point regarding origin by Pythagorean Theorem:

Point P:

OP = \sqrt{(x_{P}-x_{O})^{2}+(y_{P}-y_{O})^{2}}

If we know that x_{P} = -5, y_{P} = -3, x_{O} = 0 and y_{O} = 0, the distance OP is:

OP = \sqrt{(-5-0)^{2}+(-3-0)^{2}}

OP \approx 5.831

Point P':

OP' = \sqrt{(x_{P'}-x_{O})^{2}+(y_{P'}-y_{O})^{2}}

If we know that x_{P'} = 5, y_{P'} = 3, x_{O} = 0 and y_{O} = 0, the distance OP' is:

OP' = \sqrt{(5-0)^{2}+(3-0)^{2}}

OP' \approx 5.831

As OP = OP', origin is the center of rotation.

Besides, P' is a multiple of P, that is:

1) (-5, -3) Given

2) ((-1)\cdot 5, (-1)\cdot 3) (-a)\cdot b = -a\cdot b

3) (-1)\cdot (5, 3) Scalar multiplication of a vector/Result.

The value of the scalar proves that P experimented a 180º rotation about the origin. Hence, the correct answer is A.

ii) If Q = (-4, -5) and the same operation described in item i) is used, then, the location of Q' is:

Q' = (-1)\cdot Q

Q' = (-1) \cdot (-4,-5)

Q' = ((-1)\cdot (-4), (-1)\cdot (-5))

Q' = (4, 5)

Which corresponds to option C.

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Please help me on this question asap!
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Answer:

see explanation

Step-by-step explanation:

ΔABE and ΔACD are similar hence the ratios of corresponding sides are equal, that is

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(b)

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