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kvv77 [185]
3 years ago
5

GIVING BRAINLIEST!!!!!!

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0
A mistake first occurs in step 1. (24+3+10) is not equal to (8+10). It is equal to (27+10).
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There are 12 face cards in a deck of standard playing cards and 20 even numbered cards (2; 4; 6; 8; 10 in each suit). what is th
FromTheMoon [43]
The probability of drawing a face card is 12/52
the probability of drawing an even number is 20/52
face cards and even numbered cards do not overwrap, so no need to subtract anything
Add up: 12/52+20/52=32/52=0.6154
5 0
3 years ago
The number of pumps in use at both a six-pump station and a four-pump station will be determined. Give the possible values for e
notsponge [240]

Answer:

a. T = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

b. X = { -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}

c. U = {0, 1, 2, 3, 4, 5, 6}

d. Z = {0, 1, 2}

Step-by-step explanation:

n1 = 6 pumps

n2 = 4 pumps

a. The total number of pumps in use:

The number of pumps in use can range from 0 (no pumps used in both stations) to 10 (all pumps used in both stations), assuming all integers in between. Thus, the set T is:

T = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

b. The difference between the numbers in use at stations 1 and 2 can range from -4 (no pumps in station 1 and all pumps in station 2 being used) to 6 (all pumps in station 1 and no pumps in station 2 being used), assuming all integers in between. Thus, the set X is:

X = { -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}

c. The maximum number of pumps in use at either station is given by the possible numbers of pumps at use in station 1 (From 0 to 6). The set U is:

U = {0, 1, 2, 3, 4, 5, 6}

d. The number of stations having exactly two pumps in use can be neither, one or both. The set Z is:

Z = {0, 1, 2}

7 0
3 years ago
How to solve 1300 ÷ 26 by using multiplication
aleksley [76]
You multiply 26 x 50 that equals 1,300
8 0
3 years ago
Oh geez. I really need to understand word problems better...
ser-zykov [4K]
60/100=3/5 is the answer
7 0
3 years ago
In randomly generated list of numbers from 0 to 4, the chance that each
Alex_Xolod [135]
False, there are 5 possible outcomes
0
1
2
3
4
So the chance of each number is 1/5 or 20%
4 0
3 years ago
Read 2 more answers
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