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kvv77 [185]
3 years ago
5

GIVING BRAINLIEST!!!!!!

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0
A mistake first occurs in step 1. (24+3+10) is not equal to (8+10). It is equal to (27+10).
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Find the surface area of the prism.
alukav5142 [94]

Answer:

A: 6.5 ft

Step-by-step explanation:

Hopefully this helps

4 0
3 years ago
Read 2 more answers
Which expression is equivalent to (4g3h2k4)3
RSB [31]

Answer:

d) 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

      \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}    = 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

           =     \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

By using

        (ab)ⁿ = aⁿbⁿ

         \frac{a^{m} }{a^{n} } = a^{m-n}

   =     \frac{(4)^{3} g^{9} h^{6}k^{12} )  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

After simplification , we get

  = 8g^{9}g^{-3} h^{6} h^{-2} k^{12}  - (h^{5} k^{3} )^{5}

 = 8g^{9-3}h^{6-2}  k^{12}  - (h^{5} k^{3} )^{5}

= 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

3 0
3 years ago
Find the area of the sector with a central angle of 120° and a radius of 8 inches. Leave in terms of π
soldier1979 [14.2K]
Centralangle/360 times area of circle=sector area


120/360 times pi8²=
(1/3)(64pi)=64pi/3 square inches
8 0
3 years ago
Read 2 more answers
I needdd helpp :)))))
NeTakaya
I can’t see the scenario on top so can’t rlly help u out sorry
3 0
2 years ago
A container ship left port last week caring some good weighing a total of 125,890 tons today I stopped in another port to unload
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

You need to be specific.  Did the weight decrease by 60 tons or 60 pounds?  I assume tons, but in math, you can't assume.

This problem seems overly simple, so I am wondering if some information is missing.  With the given information and assuming the decrease was in fact 60 tons, you would have:

125,890 - 60 = 125,830 tons

8 0
3 years ago
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