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3 years ago

Find the perimeter and area of a rectangle with a length of 3.4cm and a width of 4.3cm

Mathematics

2 answers:

lubasha [3.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

The formula for the perimeter of a rectangle of length L and width W is

P = 2L + 2W. In this particular problem, P = 2(3.4 cm) + 2(4.3 cm), or

P = 6.8 cm + 8.6 cm, or P = 15.4 cm

The formula for the area of a rectangle of length L and width W is A = L * W.

In this problem, the area is A = (3.4 cm)(4.3 cm) = 14.62 cm^2 = A

zimovet [89]3 years ago

5 0

Answer:

perimeter of a rectangle

=2×(L+B)

=2×(4.3+3.4)

=2×7.7

=15.4

Area of a rectangle

=L×B

=4.3×3.4

=146.2

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3 years ago

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2 years ago

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3 years ago

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garri49 [273]

Answer:

Step-by-step explanation:

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3 years ago

Chris can be paid in one of two ways. Plan A is a salary of $490 per month, plus a commission of 9% of sales. Plan B is a sal

Tanya [424]

Step-by-step explanation:

Explanation:

First, when dealing with percents, "Percent" or "%" means "out of 100" or "per 100", Therefore x% can be written as

x/100.

The expression for Plan A can be written as:

490+(9/100)s where s is the sales for the month.

The expression for Plan B can be written as:

826+(3/100)s

The question we are being asked is when is Plan A > Plan B. So, we can write and solve this inequality:

490+(9/100)s>826+(3/100)s

490+(9/100)s−490−(3/100)s>826+(3/100)s−490−(3/100)s

490−490+(9/100)s−(3/100)s>826−490+(3/100)s−(3/100)s

0+(9/100)s−(3/100)s>826−490+0

(9/100)s−(3/100)s>826−490

(9/100−3/100)s>336

(6/100)s>336

(100/6)×(6/100)s>(100/6)×336

s> 33600/6

s>5,600

Plan A is better when sales for the month are greater than $5,600.

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4 years ago