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posledela
3 years ago
10

The diameter is 32. What is the circumference to the nearest tenth

Mathematics
2 answers:
Zinaida [17]3 years ago
8 0

Answer:

100.531 But, to the nearest tenth the answer will be 100.5, so 100.5 is the answer

i know this isn't what you wanted but imma give you more information

Radius

16.00001

Diameter

32.00002

Circumference

100.531

Area

804.2487

Goryan [66]3 years ago
6 0

Answer:

100.50

Step-by-step explanation:

Raduis = 16

Diameter = 32

2 * π * 16 = 2 * π * 16 = 100.531

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What is the pattern in the sequence below? 2, 5, 10, 17, 26, …
Mademuasel [1]

Answer:

It goes in order of odds.

Step-by-step explanation:

2+3=5

5+5=10

10+7=17

17+9=26

and so on.

6 0
4 years ago
A grocery store sells a bag of 6 oranges for $4.80. If Austin spent $8.00 on oranges, how many did he buy
boyakko [2]

Answer:

10 oranges

Step-by-step explanation:

6 oranges is sold for $4.80

1 orange= 4.80/6

= $0.8

Austin spent $8.00 on oranges, then the amount of oranges he bought with this amount can be calculated as follows

= 8/0.8

= 10 oranges

4 0
3 years ago
Lowest common multiple of 3,4 and 5
inessss [21]
2x2x3x5=60
The LCM is 60
8 0
3 years ago
Read 2 more answers
Write an expression to represent: Eight more than the product of two and a number xxx.
monitta

Answer:

8+2X is the expression of eight more than the product of two and a number

8 0
3 years ago
A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender​ selecti
Andrews [41]

Answer:

(a) Null Hypothesis, H_0 : p = 0.50

    Alternate Hypothesis, H_A : p > 0.50

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed.

(e) The value of z test statistics is 0.96.

(f) The P-value is 0.1685.

(g) At 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) We conclude that the proportion of baby girls is equal to 0.50.

Step-by-step explanation:

We are given that a 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender​ selection, the proportion of baby girls is greater than 0.5.

Assume that sample data consists of 78 girls in 144 ​births.

Let p = <u><em>population proportion of baby girls</em></u>

(a) So, Null Hypothesis, H_0 : p = 0.50     {means that the proportion of baby girls is equal to 0.50}

Alternate Hypothesis, H_A : p > 0.50     {means that the proportion of baby girls is greater than 0.50}

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed as in the alternative hypothesis we are concerned for proportion of baby girls that is greater than 0.50.

(e) The test statistics that would be used here <u>One-sample z test for proportions</u>;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of baby girls =  \frac{78}{144} = 0.54

            n = sample of births = 144

So, <u><em>the test statistics</em></u>  =  \frac{0.54-0.50}{\sqrt{\frac{0.54(1-0.54)}{144} } }  

                                       =  0.96

The value of z test statistics is 0.96.

(f) <u>The P-value of the test statistics is given by;</u>

            P-value = P(Z > 0.96) = 1 - P(Z < 0.96)

                          = 1 - 0.8315 = 0.1685

<u></u>

(g) <u>Now, at 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.</u>

(h) Since our test statistic is less than the critical value of z as 0.96 < 1.282, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region (which was to the right of value of 1.282) due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the proportion of baby girls is equal to 0.50.

7 0
3 years ago
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