Answer:
Step-by-step explanation:
The range, in a layman language, is a set of values for which f(x) exist. Hence suppose our pre-image is 0-6,and since f(x)=20x+4 ,then
When x=0, f(x)= 4
When x=1, f(x)=24
When x=2, f(x)=44
When x=3, f(x)= 64
When x=4, f(x)=84
When x=5,f(x)=104
When x=6, f(x)=124
Hence the answer is B.
You would want to make it into an addition problem that looks like this:
2x²+3x-4
+ x² - x - 2
___________
3x² + 2 - 6
<u>Given</u><u> info</u><u>:</u><u>-</u>
Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Find the perimeter of the field ?
<u>Explanation</u><u>:</u><u>-</u>
Given that
rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Let consider a rhombus ABCD
Let AC = (d1) = 42 cm
Let BD = (d2) = 56 cm
We know that
The digonals of a rhombus bisects each other at 90°.
AC = AO+OC
⇛ AC = 2 AO = 2 OC
⇛ AO = OC = AC/2
⇛ AO = OC = 42/2 = 21 cm
and
BD = BO+OD
⇛ BD = 2 BO = 2 OD
⇛ BO = OD = BD/2
⇛ BO = OD = 56/2 = 28 cm
We have,
∆AOB is a right angled triangle
By Pythagoras theorem,
AB² = AO²+OB²
⇛ AB² = 21²+28²
⇛ AB² = 441+784
⇛ AB² = 1225
⇛ AB = ±√1225
⇛ AB = ±35
AB is the length of the side which cannot be negative.
AB = 35 cm
We know that
All sides are equal in a rhombus
⇛ AB = BC = CD = DA
As we know
The Perimeter of a rhombus = 4×Side units
The perimeter of the rhombus ABCD
⇛ 4AB = 4BC = 4CD = 4DA
⇛ 4×35 cm
⇛ Perimeter = 140 cm
<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>
Answer:
no
Step-by-step explanation:
theres no common theme between the x and y variable
Answer:
A) The sentence introduces readers to the paragraphs main idea.
Step-by-step explanation:
It does not talk about technology, it is not a new idea, and it is not saying anything negative.
