<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B5%20%7D%20%2B%20%20%5Cfrac%7B3%7D%7B20%7D%20%20%3D%20" id="TexFormula1" ti

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Dahasolnce [82]

3 years ago

tle=" \frac{4}{5 } + \frac{3}{20} = " alt=" \frac{4}{5 } + \frac{3}{20} = " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

____ [38]3 years ago

8 0

The answer is 19/20
Hope this helps

Lisa [10]3 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{4}{5}+\frac{3}{20}\\ \\ \frac{4}{5}\left(\frac{4}{4}\right)+\frac{3}{20}\\ \\ \frac{16+3}{20}\\ \\ \frac{19}{20}$

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allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

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Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

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Step-by-step explanation:

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