<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B5%20%7D%20%2B%20%20%5Cfrac%7B3%7D%7B20%7D%20%20%3D%20" id="TexFormula1" ti

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Dahasolnce [82]

3 years ago

tle=" \frac{4}{5 } + \frac{3}{20} = " alt=" \frac{4}{5 } + \frac{3}{20} = " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

____ [38]3 years ago

8 0

The answer is 19/20
Hope this helps

Lisa [10]3 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{4}{5}+\frac{3}{20}\\ \\ \frac{4}{5}\left(\frac{4}{4}\right)+\frac{3}{20}\\ \\ \frac{16+3}{20}\\ \\ \frac{19}{20}$

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What is the equation of this line?

igor_vitrenko [27]

Answer:

Y=4

Step-by-step explanation:

The line is horizontal, which means that variable would be 4. The line starts at 4, which mean the equivalent of the variable is 4.

7 0

2 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.