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guajiro [1.7K]
3 years ago
14

The coordinates of which point are (–3, –6)? On a coordinate plane, point A is (negative 3, 6), point B is (negative 6, negative

3), point C is (negative 3, negative 6), and point D is (3, negative 6). point A point B point C point D
Mathematics
2 answers:
lana [24]3 years ago
8 0

Given:

The coordinates of a point are (-3,-6).

To find:

The point on the coordinate plane whose coordinates are (-3,-6).

Solution:

From the given information of coordinate plane, it is clear that

Coordinates of point A are (-3, 6).

Coordinates of point B are (-6,-3)

Coordinates of point C are (-3,-6)

Coordinates of point D are (3,-6)

It is clear that, only point C has coordinates (-3,-6).

So, the required point is C.

Therefore, the correct option is C.

Zina [86]3 years ago
4 0

Answer: C.) -3,-6

Step-by-step explanation:

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Solnce55 [7]

Answer:

B. x=5, y=4

Step-by-step explanation:

the tiny triangle is 3x smaller so just divide those numbers by three

7 0
2 years ago
which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

6 0
3 years ago
Stairs that measure 22 feet long are used to let passengers off an airplane. The distance from the bottom of the stairs to the p
elena55 [62]

Answer:

A=11

C=22

B=19.05 feet

6 0
3 years ago
Read 2 more answers
What is the best estimate for the width of your index finger
Len [333]
I don’t know for sure by 1 cm is a good guess.
8 0
3 years ago
What is the length of the major axis of the conic section shown below?
sveticcg [70]

\dfrac{(x-2)^2}{49}+\dfrac{(y+5)^2}{36}=1

The equation of a elipse:

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

The length of the major axis is equal 2a if a > b or 2b if b > a.

We have

a^2=49\to a=\sqrt{49}=7\\\\b^2=36\to b=\sqrt{36}=6\\\\a > b

therefore the length of the major axis is equal 2 · 7 = 14.

7 0
3 years ago
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