Answer:
2 m/s².
Explanation:
The forces acting on the crate have been shown in the figure below.
Net force acting on the crate in the horizontal direction = 400 - 250 = 150 N towards right.
For the forces of vertical direction we can write,
Normal force = 150 + Mg = 150 + 250 = 400 N (here g = 10 m/s² have been taken)
The magnitude of frictional force that will act on the crate = μ × Normal force
So, Frictional force = 0.25 × 400 = 100 N
Thus, the net force that will cause acceleration in the crate will be
Force in the right direction - frictional force
= 150 - 100 = 50 N
As we know,
Acceleration = 
= 
= 2 m/s²
So, the net acceleration in the crate will be 2 m/s².
Answer:
Req = 564 Ω
Explanation:
The equivalent resistance between R1 and R2:
1/R =1/R1 + 1/R2
1/R =1/960 + 1/640
1/R = 1/384
R = 384
Now, the equivalent resistance between R and R3:
Req = 384 + 180
Req = 564 Ω
Answer:
Answer:
4, 2, 5, 3, 1
Explanation:
The neuron remains at RMP unless stimulated. The stimulus results in opening of stimulus channels, this causes depolarization. if the extent of depolarization reaches to the level of threshold, the sodium and potassium channels begin opening but potassium channels are slow to open. Hence at first sodium goes out causing further depolarization until it reaches the peak at which the potassium channels open and the sodium channels close. This causes the potassium to rush our causing repolarization i.e. return of the membrane potential to RMP but the potassium channels are slow to close and it leads to hyperpolarization (undershoot) making the membrane potential more negative due to excessive movement of potassium outside the cell. Once the potassium channels close, the leak channels and Na K pump acts to return the potential to RMP.
Explanation:
A.simple machine hpoe u get it
