Answer:
Explanation:
Let T be the tension 
For linear motion of hoop downwards 
mg -T = ma , m is mass of the hoop . a is linear acceleration of CG of hoop . 
For rotational motion of hoop 
Torque by tension 
T x R ,      R is radius of hoop. 
Angular acceleration be α, 
Linear acceleration a = α R 
So TR = I  α
= I  a / R 
a = TR² / I 
Putting this value in earlier relation 
mg -T = m TR² / I
mg = T ( 1 + m R² / I ) 
T = mg / ( 1 + m R² / I ) 
mg / ( 1 + R² / k² )
Tension is less than mg or weight because denominator of the expression is more than 1.