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ExtremeBDS [4]
2 years ago
9

When a fighter pilot feels massive amounts of force when their planes turn quickly applies to_

Physics
1 answer:
sattari [20]2 years ago
3 0

Answer:

The answer is A - Newtons First Law

Explanation:

The law is what we call "Inertia". The law basically states that an object wants to stay where it is. We can see the effect from our cars, albeit with less force. When the car turns right, your body goes left, opposite to the turns direction due to us moving position in the car.

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What information could you gather about a star if its light curve had multiple
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The information that could be gathered about a star whose light curve has multiple symmetrical depths is ; The shape and surface variegation of the star

The light curves of a KBO ( moons and stars ) are measured as a rate of the brightness of a star in relation to time. therefore the study of the light curve having multiple symmetrical depths ( depth of brightness ) will give an information about the shape/size and the surface variegation of the star

Hence we can conclude that The information that could be gathered about a star whose light curve has multiple symmetrical depths is ; The shape and surface variegation of the star

Learn more : brainly.com/question/19573734

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2 years ago
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7.a railway truck A of a mass of 2000kg moves westwards with a velocity of 3m/s. It collides with a stationary truck B 1200kg, l
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Answer:

9. A 1500kg car traveling +6m/s with a 2000kg truck at rest. The vehicles collide, but do not stick together. The car has a velocity -3m/s after the collision. What is the velocity of the truck? a. What type of collision occurred above?

6 0
2 years ago
Is directly proportional to the length and resistivity of the conductor.
aliya0001 [1]

Answer:

B) resistance

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the resistance of a wire is proportional to its length, and inversely proportional to its cross-sectional area.

8 0
3 years ago
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A spring is stretched from x=0 to x=d, where x=0 is the equilibrium position of the spring. It is then compressed from x=0 to x=
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Answer:

The same amount of energy is required to either stretch or compress the spring.

Explanation:

The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:

U=\frac{1}{2}k (\Delta x)^2

where

k is the spring constant

\Delta x is the stretch/compression of the spring

In the first case, the spring is stretched from x=0 to x=d, so

\Delta x = d-0=d

and the amount of energy required is

U=\frac{1}{2}k d^2

In the second case, the spring is compressed from x=0 to x=-d, so

\Delta x = -d -0 = -d

and the amount of energy required is

U=\frac{1}{2}k (-d)^2= \frac{1}{2}kd^2

so we see that the amount of energy required is the same.

7 0
3 years ago
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