Answer:
The answer is the digit 3 is on the Ten-Thousandths place.
Step-by-step explanation:
Answer:
The equation that best represents the line that is parallel to 3x - 4y = 7 and passes through the point (-4, -2) is y = 3/4x + 1.
Step-by-step explanation:
3x - 4y = 7 and (-4, -2)
First, solve for y in the equation:
3x - 4y = 7
-4y = -3x + 7
4y = 3x - 7
y = 3/4x - 7/4
m = 3/4 (This will be the slope of the parallel line.) and (-4, -2)
Use the point-slope equation to find the equation that will best represent a parallel line:
y − y1 = m(x − x1)
y - -2 = 3/4(x - -4)
y + 2 = 3/4x + 3 (the 4s cancel out)
(3/4 x 4/1 = 3)
y = 3/4x + 1
The graph that I attached is what these two equations would look like graphed. I am not sure what you mean by two options, I'm sorry!
I think the answer is 745
<h3>Answer: The month of April</h3>
More accurately: The correct time will be shown on April 4th if it is a leapyear, or April 5th if it is a non-leapyear. It takes 60 days for the clock to realign, which is the same as saying "the clock loses 24 hours every 60 days".
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Explanation:
The following statements shown below are all equivalent to one another.
- Clock loses 1 second every 1 minute (original statement)
- Clock loses 60 seconds every 60 minutes (multiply both parts of previous statement by 60)
- Clock loses 1 minute every 1 hour (time conversion)
- Clock loses 60 minutes every 60 hours (multiply both parts of previous statement by 60)
- Clock loses 1 hour every 2.5 days (time conversion)
- Clock loses 24 hours every 60 days (multiply both parts of previous statement by 24)
Use a Day-Of-Year calendar to quickly jump ahead 60 days into the future from Feb 4th (note how Feb 4th is day 35; add 60 to this to get to the proper date in the future). On a leapyear (such as this year 2020), you should land on April 4th. On a non-leapyear, you should land on April 5th. The extra day is because we lost Feb 29th.
The actual day in April does not matter as all we care about is the month itself only. Though it's still handy to know the most accurate length of time in which the clock realigns itself.
when i calculated the ans came as 20.83333333
just cross verify it but from 21 papers 126 tickets can be made
